这是我的数据库查询,当我使用 sortby公司时它不起作用我有48000条记录,但它只显示18000条记录。 Sortby状态,联系人,城市都工作正常。任何帮助都会很感激
public static function retreiveCandidates($status,$alpha=NULL,$dash=NULL,$statusid,$sortby=NULL){
DB::enableQueryLog();
$query = DB::table('candidates')->select('candidates.candidateid','candidates.firstname','candidates.lastname','candidates.imageext','candidates.middlename','candidates.personal_email','candidates.city','candidates.mobile','candidates.title_id','candidates.status','candidates.state','candidates.isverified','candidates.candidate_statusid','candidates.sendinvitation','candidates.ismerged','candidates.imagekey','candidates.candidatekey')->where('candidates.status',$status);
if($alpha!=''){
$query = $query->where('candidates.firstname', 'like', $alpha . '%');
}
if($statusid !=''){
$query = $query->where('candidates.candidate_statusid',$statusid);
}
if($dash !=''){
$result = $query->orderBy('candidates.created_at', 'desc')->limit(7)->get();
}
if($sortby == NULL){
$query = $query->orderBy('candidates.firstname', 'asc') ;
}elseif($sortby == 'company'){
$query = $query->join('candidates_company','candidates_company.candidateid','=','candidates.candidateid')->join('company','company.companyid','=','candidates_company.companyid')->where('candidates_company.status','1')->groupBy('candidates.candidateid')->orderBy('company.company', 'asc')->orderBy('candidates.candidateid', 'asc') ;
}elseif($sortby == 'status'){
$query = $query->join('candidate_status','candidate_status.statusid','=','candidates.candidate_statusid')->orderBy('candidate_status.statusorder', 'asc') ;
}elseif($sortby == 'contact'){
$query = $query->orderBy('candidates.firstname', 'asc');
}elseif( $sortby == 'city'){
$query = $query->orderBy('candidates.city', 'asc') ;
}elseif( $sortby == 'state'){
$query = $query->orderBy('candidates.state', 'asc') ;
}
$result = $query->paginate(PAGELIMIT);
$d= DB::getQueryLog();
return $result;
}
打印dbquery时得到的内容
Array
(
[0] => Array
(
[query] => select count(*) as aggregate from `rsi_candidates` inner join `rsi_candidates_company` on `rsi_candidates_company`.`candidateid` = `rsi_candidates`.`candidateid` inner join `rsi_company` on `rsi_company`.`companyid` = `rsi_candidates_company`.`companyid` where `rsi_candidates`.`status` = ? and `rsi_candidates_company`.`status` = ? group by `rsi_candidates`.`candidateid`
[bindings] => Array
(
[0] => 1
[1] => 1
)
[time] => 1036.83
)
[1] => Array
(
[query] => select `rsi_candidates`.`candidateid`, `rsi_candidates`.`firstname`, `rsi_candidates`.`lastname`, `rsi_candidates`.`imageext`, `rsi_candidates`.`middlename`, `rsi_candidates`.`personal_email`, `rsi_candidates`.`city`, `rsi_candidates`.`mobile`, `rsi_candidates`.`title_id`, `rsi_candidates`.`status`, `rsi_candidates`.`state`, `rsi_candidates`.`isverified`, `rsi_candidates`.`candidate_statusid`, `rsi_candidates`.`sendinvitation`, `rsi_candidates`.`ismerged`, `rsi_candidates`.`imagekey`, `rsi_candidates`.`candidatekey` from `rsi_candidates` inner join `rsi_candidates_company` on `rsi_candidates_company`.`candidateid` = `rsi_candidates`.`candidateid` inner join `rsi_company` on `rsi_company`.`companyid` = `rsi_candidates_company`.`companyid` where `rsi_candidates`.`status` = ? and `rsi_candidates_company`.`status` = ? group by `rsi_candidates`.`candidateid` order by `rsi_company`.`company` asc, `rsi_candidates`.`candidateid` asc limit 10 offset 0
[bindings] => Array
(
[0] => 1
[1] => 1
)
[time] => 454.11
)
)
答案 0 :(得分:1)
对未来参考的建议,使用" ==="而不是" ==",第二个将在一些最尴尬的案例中产生真实。
进入问题,您的搜索只有
其中(' candidates_company.status'' 1&#39)
可能会缩小搜索结果的范围,但实际上并没有看到我无法确定问题的表格,但我无法看到除此之外的任何其他内容正在检索的结果数量。
答案 1 :(得分:0)
创建候选人模型
php artisan make:model Candidate
这将在您的app文件夹中创建一个模型文件candidate.php。该文件看起来像
<?php
namespace App;
use Illuminate\Database\Eloquent\Model;
class Candidate extends Model
{
protected $table = 'candidate'; //give your table name here
}
现在您可以在控制器中访问您的候选模型,如
use App\Candidate;
class CandidateController extends Controller
{
$candidates= App\Candidate::orderBy('company')->get(); //select by orderby
}
希望这有帮助