Question

我正在写一本书，用raspberry pi学习python，我有点难过，因为我收到了这种类型的错误。我的IDE在下面吐出这条消息，我不确定它是否是构造函数类型问题

control_window = TurtleControl（babbage）TypeError：使用错误的参数类型调用'PySide.QtGui.QWidget'： PySide.QtGui.QWidget（Turtle）支持的签名： PySide.QtGui.QWidget（PySide.QtGui.QWidget = None， PySide.QtCore.Qt.WindowFlags = 0）

import turtle
import sys
from PySide.QtCore import *
from PySide.QtGui import *


class TurtleControl (QWidget):
    def __init_(self, turtle):
                super(TurtleControl, self) .__init__()
                self.turtle = turtle

                self.left_btn = QPushButton("Left", self)
                self.right_btn = QPushButton("Right", self)
                self.move_btn = QPushButton("Move", self)
                self.distance_spin = QSpinBox()


                self.controlsLayout = QGridLayout()
                self.controlsLayout.addWidget(self.left_btn, 0, 0)
                self.controlsLayout.addWidget(self.right_btn, 0, 1)
                self.controlsLayout.addWidget(self.distance_spin,1, 0)
                self.controlsLayout.addWidget(self.move_btn,1, 1)
                self.setLayout(self.controlsLayout)

                self.distance_spin.setRange(0, 100)
                self.distance_spin.setSingleStep(5)
                self.distance_spin.setValue(20)

                self.move_btn.clicked.connect(self.move_turtle)
                self.move_btn.clicked.connect(self.move_turtle_right)
                self.move_btn.clicked.connect(self.move_turtle_left)

# set up turtle
window = turtle.Screen()
babbage = turtle.Turtle()

# Create a QT application
app = QApplication(sys.argv)
control_window = TurtleControl(babbage)
control_window.show()

# Enter QT application main loop
app.exec_()
sys.exit()

参数类型错误，PySide

0 个答案: