Question

serializers.py

from django.contrib.auth.models import User
from engine.models import Game
from rest_framework import serializers

class GameSerializer(serializers.ModelSerializer):
    class Meta:
        model = Game
        fields = (
            'game_name',
            'level',
            'game_type',
            'creator',
            'id',
        )

我希望得到creator.username，因为creator只返回作为创建者的用户对象的id的整数。我怎样才能获得creator.username而不是creator？

Answer 1

试试这个。希望creator字段是只读的，并从request.user

等视图中分配

from django.contrib.auth.models import User
from engine.models import Game
from rest_framework import serializers

class GameSerializer(serializers.ModelSerializer):
    creator = serializers.CharField(read_only=True, source='creator.username')
    class Meta:
        model = Game
        fields = (
            'game_name',
            'level',
            'game_type',
            'creator',
            'id',
        )

注意：这会使creator字段为只读。如果您计划从序列化程序添加它，请为creator.user名称使用单独的名称。就像下面的例子一样

class GameSerializer(serializers.ModelSerializer):
    creator_name = serializers.CharField(read_only=True, source='creator.username')
    class Meta:
        model = Game
        fields = (
            'game_name',
            'level',
            'game_type',
            'creator',
            'creator_name',
            'id',
        )

Answer 2

您可以覆盖序列化方法字段，如下所示，将creator.username设为creator，如下所示：

class GameSerializer(serializers.ModelSerializer):
    creator = serializers.SerializerMethodField(read_only=True)

    def get_creator(self, obj):
        # obj is model instance
        return obj.creator.username

    class Meta:
        model = Game
        fields = (
            'game_name',
            'level',
            'game_type',
            'creator',
            'id',
        )

在序列化器中获取字段的属性（django rest框架）

2 个答案: