Question

地狱全部。这个问题让我不知所措，因为我无法弄清楚我做错了什么。我想要的只是收集变量并将它们传递给函数，但是只要输入函数运行的第一个变量，就可以了？

#include <iostream>
#include <string>
#include <fstream>

using namespace std;
void avg_rain(string, string);
int main()
{
    string file, unit;

    //Prompt user for file names, and assign to character array
    cout << "Please type the file names with extentions that you would like to open, seperate file names with spaces. \nfile name(s) :";
    cin >> file;

    //Prompt user for measurement unit
    cout << "Please type the unit you would like measurments to be converted to (mm, cm, in)\nUnit : ";
    cin >> unit;

    //execute function with passed through parameters
    avg_rain(file, unit);

    system("pause");
return 0;
}

void avg_rain(string ffile ,string funit )
{
    cout << ffile;
}

即使没有为第二个变量输入任何内容，这也是我的输出。

[OUTPUT：]

Please type the file names with extentions that you would like to open, seperate file names with spaces.

file name(s) :hello world
Please type the unit you would like measurments to be converted to (mm, cm, in)

Unit : hello

Press any key to continue . . .

C ++在被调用之前执行一个函数？

0 个答案: