Question

我需要帮助理解为什么我不能在使用CASE

的选择列表中使用GROUP BY字段

这是查询

select 
    CASE WHEN COUNT(AB9_NUMOS) = 0 THEN 'P' ELSE 'E' END AS result,
    AAG_DESCRI,
    count(AB6_STATUS) as count
from AB6010
    left join AB7010 on AB7_FILIAL = AB6_FILIAL and AB7_NUMOS = AB6_NUMOS and AB7010.D_E_L_E_T_ = ' '
    left join AAG010 on AAG_CODPRB = AB7_CODPRB and AAG010.D_E_L_E_T_ = ' ' 
    left join AB9010 on AB9_FILIAL = AB6_FILIAL AND AB9_NUMOS = AB6_NUMOS+'01' and AB9010.D_E_L_E_T_ = ' '
where 
    ab6010.D_E_L_E_T_ = ' '
    and AB6_FILIAL = '01'
    and AB6_STATUS = 'A'
group by result, AAG_DESCRI

在此查询中，我正在尝试对表AB6010中的行进行分类， AB6010（服务订单）中的每一行在AB9010上都可以没有或N个引用（如果我的AB6010行在AB9010中有任何引用意味着我的服务订单已经被执行）。所以我要做的是：

如果AB6010在AB9010中有0个引用，则其状态为“P”

如果AB6010在AB9010中有1个或多个引用，则其状态应为“E”

然后我想按此状态进行分组，并按AAG_DESCRI（这意味着它是哪种服务顺序）进行分组，并显示有多少AB6010类型X（aag_descri）行是'P'，有多少是'E' ”。但是当我运行查询时，我收到以下错误

Invalid column name 'result'.

我的预期结果应该是

result     AAG_DESCRI                     count
---------- ------------------------------ -----------
E          CORTE A PLASMA                 7
E          CORTE E DOBRA                  31
E          FABRICACAO                     7
E          MANUTENCAO                     4
E          RETORNO/GARANTIA               3
P          CORTE A PLASMA                 3
P          CORTE E DOBRA                  10
P          FABRICACAO                     3
P          MANUTENCAO                     1
P          RETORNO/GARANTIA               8

Answer 1

您可以从以下cte中受益。

;with cte (result,AB6_NUMOS,AAG_DESCRI) as (
   select 
            CASE WHEN COUNT(AB9_NUMOS) = 0 THEN 'P' ELSE 'E' END AS result,
            AB6_NUMOS,
            AAG_DESCRI
   from AB6010
            left join AB7010 on AB7_FILIAL = AB6_FILIAL and AB7_NUMOS = AB6_NUMOS and AB7010.D_E_L_E_T_ = ' '
            left join AAG010 on AAG_CODPRB = AB7_CODPRB and AAG010.D_E_L_E_T_ = ' ' 
            left join AB9010 on AB9_FILIAL = AB6_FILIAL AND AB9_NUMOS = AB6_NUMOS+'01' and AB9010.D_E_L_E_T_ = ' '
   where 
            ab6010.D_E_L_E_T_ = ' '
            and AB6_FILIAL = '01'
            and AB6_STATUS = 'A'
            group by AB6_NUMOS,AAG_DESCRI
)
select result, AAG_DESCRI, count(AB6_NUMOS) as count
from cte
group by result, AAG_DESCRI
order by result,AAg_DESCRI

Answer 2

使用子查询

select 
from (select AAG_DESCRI, COUNT(AB9_NUMOS) as c1, COUNT(AB6_STATUS) as c2 
           , CASE WHEN COUNT(AB9_NUMOS) = 0 THEN 'P' ELSE 'E' END AS result 
      from from AB6010 
      group by AAG_DESCRI 
     ) t

在GROUP BY中使用CASE列

2 个答案: