Question

基本上，该函数返回一个新字符串，该字符串具有电话号码，其中任何字母字符出现在原始文件中，并转换为其等效数字。格式：XXX-XXX-XXXX。

这是我的功能代码：

def translate_phone(xxx):
phonenumber = ''
for alpha in xxx:
    if  alpha =='A' or alpha =='B' or alpha == 'C' :
        phonenumber.append('2')
    elif alpha == 'D' or alpha == 'E' or alpha =='F':
        phonenumber.append('3')
    elif alpha == 'G' or alpha =='H' or alpha =='I':
        phonenumber.append('4')
    elif alpha == 'J' or alpha =='K' or alpha =='L':
        phonenumber.append('5')
    elif alpha == 'M' or alpha == 'N' or alpha =='O':
        phonenumber.append('6')
    elif alpha == 'P' or alpha =='Q' or alpha =='R' or alpha =='S':
        phonenumber.append('7')
    elif alpha == 'T' or alpha =='U' or alpha =='V':
        phonenumber.append('8')
    elif alpha == 'W' or alpha =='X' or alpha == 'Y' or alpha =='Z':
        phonenumber.append('9')
    phonenumber = phonenumber + alpha
print(phonenumber)

这是我在另一个模块中的主要代码：

from _functions import translate_phone
xxx = input('Enter the Number in the following format XXX-XXX-XXXX: ')
xxx = xxx.split('-')
translate_phone(xxx)

错误？每次我运行它都会得到相同的输入。

Enter the Number in the following format XXX-XXX-XXXX: ABC-123-QWER
ABC123QWER

如果有人能暗示我做错了什么或者只是纠正我的错误，我将不胜感激。

Answer 1

您需要删除代码xxx = xxx.split('-')并替换您的函数：

def translate_phone(xxx):
  phonenumber = list()
  for alpha in xxx:
      if  alpha in ('A', 'B', 'C'):
          phonenumber.append('2')
      elif alpha in ('D', 'E', 'F'):
          phonenumber.append('3')
      elif alpha in ('G', 'H', 'I'):
          phonenumber.append('4')
      elif alpha in ('J', 'K', 'L'):
          phonenumber.append('5')
      elif alpha in ('M', 'N', 'O'):
          phonenumber.append('6')
      elif alpha in ('P', 'Q', 'R', 'S'):
          phonenumber.append('7')
      elif alpha in ('T', 'U', 'V'):
          phonenumber.append('8')
      elif alpha in ('W', 'X', 'Y', 'Z'):
          phonenumber.append('9')
      else:
          phonenumber.append(alpha)
  return ''.join(phonenumber)

或

def translate_phone(xxx):
  phonenumber = list()
  for alpha in xxx:
      phonenumber.append(\
              '2' if alpha in ('A', 'B', 'C') else \
              '3' if alpha in ('D', 'E', 'F') else \
              '4' if alpha in ('G', 'H', 'I') else \
              '5' if alpha in ('J', 'K', 'L') else \
              '6' if alpha in ('M', 'N', 'O') else \
              '7' if alpha in ('P', 'Q', 'R', 'S') else \
              '8' if alpha in ('T', 'U', 'V') else \
              '9' if alpha in ('W', 'X', 'Y', 'Z') else alpha)
  return ''.join(phonenumber)

没有返回正确的打印声明

1 个答案: