Question

我有两个JSON调用函数可以获取客户数据和发票数据。在我的客户端JSON响应中，我有ID和名称等。在我的发票回复中，我有客户端ID。

我需要从发票中获取客户端ID并转换为客户端名称字符串。

在我的downloadClientsJSON我创建了一个名为func downloadClientsJSON(completed: @escaping () -> ()) { let url = URL(string: "http://ex.com/app/api/clientList/get") URLSession.shared.dataTask(with: url!) { (data, response, error) in if error == nil { do { self.clients.removeAll() self.clients = try JSONDecoder().decode([ClientsList].self, from: data!) DispatchQueue.main.async { completed() } } catch { print ("Error") } } }.resume() }

的函数

ClientsList

这是import Foundation struct ClientsList:Decodable { let name: String let vatNumber: String let address: String let cap: String let city: String let prov: String let tel: String let email: String }结构：

[{"id":1,"name":"DemoClient","vatNumber":"010101010101","address":"Demo Address, 1","cap":"01010","city":"DemoCity","prov":"DP","tel":"555-1112223","email":"demo@example.com"}]

以下是JSON响应：

InvoiceViewController

在我的downloadInvoicesJSON我创建了一个名为func downloadJSON(completed: @escaping () -> ()) { let url = URL(string: "http://ex.com/app/api/invoiceList/get") URLSession.shared.dataTask(with: url!) { (data, response, error) in if error == nil { do { self.invoices.removeAll() self.invoices = try JSONDecoder().decode([InvoiceList].self, from: data!) DispatchQueue.main.async { completed() } } catch { print (error) } } }.resume() }

的函数

InvoiceList

以下是import Foundation struct InvoiceList:Decodable { let id: NSInteger let date: String let expiration: String let client: NSInteger let status: NSInteger let lines: String let total: Float }结构：

[{"id":1,"date":"01-01-2018","expiration":"01-01-2018","client":3,"status":3,"lines":"1:1","total":700},{"id":2,"date":"30-01-2018","expiration":"30-01-2018","client":4,"status":2,"lines":"1:1","total":100},{"id":3,"date":"15-02-2018","expiration":"15-02-2018","client":3,"status":3,"lines":"1:1","total":700}]

以下是JSON响应：

InvoiceViewController

该功能应该在Cid中。我如何得到结果？

Answer 1

您从http://ex.com/app/api/clientList/get获取的JSON对象应该是一个数组，参数键应该与ClientsList的属性名称相同。

struct ClientsList: Decodable {
    let name: String
    let vatNumber: String
    let address: String
    let cap: String
    let city: String
    let prov: String
    let tel: String
    let email: String
}

如果您不确定是否会在响应JSON中收到所有属性，请将该特定属性设为可选。像：

struct ClientsList: Decodable {
    let name: String
    let vatNumber: String
    let address: String
    let cap: String
    let city: String? // Not sure about receiving this property
    let prov: String? // Not sure about receiving this property
    let tel: String? // Not sure about receiving this property
    let email: String
}

http://ex.com/app/api/invoiceList/get和InvoiceList需要遵循相同的模式。

使用JSON将ID转换为用户名

1 个答案: