Question

我有表users，posts和comments，用户有很多帖子，每个帖子都有很多评论（评论表中有post_id），也有用户有很多评论，但匿名用户（评论表中的user_id）并不完全需要，下面的代码为每个帖子添加一些注释，但user_id永远不会被评论的所有者填充。我想通过在$factory->define之外的数组中注入注释来关联user_id。实际上我可以将随机user_id放在工厂内，但是随机用户总数必须与Seeder类中的值相同。

**CommentFactory.php**   

$factory->define(App\Contact::class, function (Faker $faker) {
return [
        // 'user_id' => $faker->randomElement([null, rand(0, 9)]), 
        'name' => $faker->name,
        'email' => $faker->unique()->safeEmail,
        'contact' => $faker->phoneNumber,
        'website' => $faker->domainName,
        'subject' => $faker->sentence(),
        'message' => $faker->paragraph(5),
    ];
});

**UserSeeder.php**

factory(App\User::class, 10)->create()->each(function ($user) {
   $user->posts()->saveMany(factory(App\Post::class, rand(2, 10))->make());
   $user->posts->each(function ($post) use ($user) {    
      // how to inject user_id value from here (comment factory)
      $post->comments()->saveMany(factory(App\Comment::class, rand(2, 10))->make());
   });
});

Answer 1

您可以将一组属性/值传递给make方法：

factory(App\Comment::class, rand(2, 10))->make(['user_id'=>$user->id]);

编辑：只需迭代评论并分配随机用户ID：

factory(App\Comment::class, rand(2, 10))->create()->each(function($comment){
   $comment->update(['user_id'=>\App\User::all()->random()->id]);
});

如果您想拥有随机匿名评论者：

factory(App\Comment::class, rand(2, 10))->create()->each(function($comment){
   // pick either a random user_id or null;
   $userId=array_random(\App\User::all()->random()->id, null);
   $comment->update(['user_id'=>$userId]);
});

在laravel中通过关系播种两个外键

1 个答案: