我试图通过编写可用的字节流,使用NAudio的WasapiLoopbackCapture将扬声器声音录制到波形文件中。 WasapiLoopbackCapture.DataAvailable BytesRecorded 将为0,没有声音。但是在我的情况下,即使说话者保持沉默,我也会在 BytesRecorded 中获得字节数。你能告诉我这里有什么不对吗?
class CallResponse
{
private WaveFileWriter _writer;
private WasapiLoopbackCapture _waveIn;
private string _inFile;
private string _inFileCompressed;
private int _duration;
public bool _isRecording;
public bool _speechDetected;
public CallResponse()
{
_inFile = @"C:\Naresh\test.wav";
_inFileCompressed = @"C:\Naresh\test16Hz.wav";
_waveIn = new WasapiLoopbackCapture();
_waveIn.DataAvailable += (s, e) =>
{
Console.WriteLine(e.BytesRecorded);
_writer.Write(e.Buffer, 0, e.BytesRecorded);
if (_writer.Position > _waveIn.WaveFormat.AverageBytesPerSecond * _duration)
{
Console.Write("\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\bRecording stopped...");
_waveIn.StopRecording();
}
};
_waveIn.RecordingStopped += (s, e) =>
{
if (_writer != null)
{
_writer.Close();
_writer.Dispose();
_writer = null;
}
Console.Write("\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\bCompressing Audio...");
using (var reader = new AudioFileReader(_inFile))
{
var resampler = new WdlResamplingSampleProvider(reader, 16000);
WaveFileWriter.CreateWaveFile16(_inFileCompressed, resampler);
}
_isRecording = false;
};
}
public void DisposeObjects()
{
if (_waveIn != null)
{
_waveIn.Dispose();
_waveIn = null;
}
}
public void StartRecording(int duration = 5)
{
_writer = new WaveFileWriter(_inFile, _waveIn.WaveFormat);
this._duration = duration;
_speechDetected = false;
_isRecording = true;
Console.WriteLine("\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\b\bRecording....");
_waveIn.StartRecording();
}
}
答案 0 :(得分:1)
如果正在播放音频,那么WasapiLoopbackCapture
将捕获该音频,即使它包含静音。因此,您获得非零BytesRecorded
值并没有特别的错误或令人惊讶。事实上,如果没有应用程序向正在捕获的设备发送音频,那么通常会发生的事情是您根本没有获得任何DataAvailable
回调。