TypeError：第一个参数必须是字符串或编译模式

Question

我从名为blocked_sites的数据库表中获取值。如果表blocked_sites中的第0个属性的值出现在文件items.csv的第19个或第26个字段中，则csv的该行将从csv文件中排除。我正在为此编写代码并收到此错误：

$ python csv_dupli_prev.py
Traceback (most recent call last):
  File "csv_dupli_prev.py", line 48, in <module>
    found = re.search(row[0], row1[19])
  File "/home/debarati/anaconda3/lib/python3.6/re.py", line 182, in search
    return _compile(pattern, flags).search(string)
  File "/home/debarati/anaconda3/lib/python3.6/re.py", line 300, in _compile
    raise TypeError("first argument must be string or compiled pattern")
TypeError: first argument must be string or compiled pattern

代码如下：

connection = pymysql.connect (host = "localhost", user = "root", passwd = "......", db = "city_details")          
cursor = connection.cursor ()
csv_file = csv.reader(open("items.csv", "r"))
newrows = []
cursor.execute ("select * from blocked_sites")
data4 = cursor.fetchall ()
for row in data4:
   for row1 in csv_file:
      str1 = row1[19]
      str2 = row1[26]
      found = re.search(row[0], str1)
      found1 = re.search(row[0], str2)
      if found==None and found1==None and row1 not in newrows:
         newrows.append(row1)
writer = csv.writer(open("items.csv", "w"))
writer.writerows(newrows)   

Answer 1

我在代码中更改了以下行：

cursor.execute ("select * from blocked_sites")

到此：

cursor.execute ("select content from blocked_sites")

并修复了错误。