通过AJAX通过电子邮件发送图像

时间:2011-02-11 03:18:56

标签: php jquery ajax email

使用以下代码,我可以发送附加其他服务器图像的电子邮件。

<$php
$to = "your@email.com"; 
$subject = "A test email";
$random_hash = md5(date('r', time()));

$headers = "From: email@example.com\r\nReply-To: email@example.com";
$headers .= "\r\nContent-Type: multipart/mixed; boundary=\"PHP-mixed-".$random_hash."\"";

$attachment = chunk_split(base64_encode(file_get_contents('http://www.ipadwallpapermac.com/wp-content/uploads/2010/06/adriana-lima.jpg')));

$output = "
--PHP-mixed-$random_hash;
Content-Type: multipart/alternative; boundary='PHP-alt-$random_hash'
--PHP-alt-$random_hash
Content-Type: text/plain; charset='iso-8859-1'
Content-Transfer-Encoding: 7bit

Hello World!
This is the simple text version of the email message.

--PHP-alt-$random_hash
Content-Type: text/html; charset='iso-8859-1'
Content-Transfer-Encoding: 7bit

<h2>Hello World!</h2>
<p>This is the <b>HTML</b> version of the email message.</p>

--PHP-alt-$random_hash--

--PHP-mixed-$random_hash
Content-Type: application/jpeg; name=testing.jpg
Content-Transfer-Encoding: base64
Content-Disposition: attachment

$attachment
--PHP-mixed-$random_hash--";

mail($to, $subject, $output, $headers);
?>t;

但是,当我尝试通过AJAX(jquery)使用此代码时,它会发送电子邮件但没有附件。有什么我想念的吗?

这是我的AJAX jquery脚本:

$.ajax({
    url: '&lt;?php echo site_url("ajax/email_wallpaper/".$post_details->id); ?&gt;',
    type: 'POST',
    dataType: 'json',
    data: $.param({'email':$('#email_address').val()}),
    crossDomain: true, 
    complete: function(data) {
        //called when complete
    },
    success: function(data) {
        console.log(data);
        if(data.status == 'success'){
            setTimeout(function(){
                $('#basic-modal-content .status')
                .addClass('no_bg')
                .find('p')
                .html('Success! The wallpaper has been sent to your email.');
                setTimeout('$.modal.close();', 1000);
            }, 1000);
        }
    },
    error: function(data) {
        $('#basic-modal-content .status')
        .addClass('no_bg')
        .find('p')
        .html('Please provide a valid email address.');
        console.log(data);
        console.log(data.responseText);
        //called when there is an error
    }
});

1 个答案:

答案 0 :(得分:0)

这是什么?你没有在上面提到这个site_url()函数......

$.ajax({
url: '&lt;?php echo site_url("ajax/email_wallpaper/".$post_details->id); ?&gt;',

你想要尝试的不是在你的javascript中编写任何php。

您发布的PHP的第一部分需要放入PHP文件中,以便您可以在参数中调用该文件。

代码不一定需要在该文件中,您当然可以调用php函数,但是您可以将函数文件包含在ajax将调用的文件中。

所以,而不是上面的代码,您的ajax URL参数将如下所示:

$.ajax({
url: '/email-with-attatchment.php',
type: 'POST',
dataType: 'json',
data: $.param({'email':$('#email_address').val()}),
crossDomain: true, 
complete: function(data) {
    //called when complete
},
success: function(data) {
    console.log(data);
    if(data.status == 'success'){
        setTimeout(function(){
            $('#basic-modal-content .status')
            .addClass('no_bg')
            .find('p')
            .html('Success! The wallpaper has been sent to your email.');
            setTimeout('$.modal.close();', 1000);
        }, 1000);
    }
},
error: function(data) {
    $('#basic-modal-content .status')
    .addClass('no_bg')
    .find('p')
    .html('Please provide a valid email address.');
    console.log(data);
    console.log(data.responseText);
    //called when there is an error
}

});

尝试这样做,然后尝试再次查看问题...

相关问题