我知道launch4j并没有将{J {1}}中的JRE捆绑在一起,而是必须将它放在旁边。我的问题是,我该怎么做?有没有办法让maven自动定位和复制JDK的JRE用于构建我的应用程序并将其复制到给定目录?
我尝试过这样的事情:
.exe
但该计划尚无法启动。它显示了一个立即消失的小对话框(它似乎是空白的,但它让我真的注意到它太快了。)
答案 0 :(得分:12)
更新:删除了我以前的答案并替换为经过测试的工作示例
更新2:这个pom.xml现在下载JRE tgz并解压缩它,launch4j exe使用它并且它可以工作。我添加了评论来解释它是如何工作的。
我建议只使用32位exe和JRE。使用64位JRE的唯一原因是,如果您的程序需要使用超过4 GB的RAM。
当然,现在您需要一个能够完成所有这些并安装到Program Files的安装程序。我过去曾经使用过NSIS。 NSIS有一个学习曲线,但也不算太糟糕。
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.akathist.encc</groupId>
<artifactId>mavenproject1</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>jar</packaging>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<maven.compiler.source>1.8</maven.compiler.source>
<maven.compiler.target>1.8</maven.compiler.target>
</properties>
<dependencies>
<!-- This is the win32 JRE tgz hosted by alfresco - https://mvnrepository.com/artifact/com.oracle.java/jre -->
<dependency>
<groupId>com.oracle.java</groupId>
<artifactId>jre</artifactId>
<classifier>win32</classifier>
<type>tgz</type>
<version>1.8.0_131</version>
</dependency>
</dependencies>
<repositories>
<repository>
<!-- this repository has the JRE tgz -->
<id>alfresco</id>
<url>https://artifacts.alfresco.com/nexus/content/repositories/public/</url>
</repository>
</repositories>
<build>
<plugins>
<plugin>
<!-- this is to extract the JRE tgz file we downloaded -->
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<version>2.5.1</version>
<executions>
<execution>
<phase>generate-resources</phase>
<goals>
<goal>unpack-dependencies</goal>
</goals>
<configuration>
<includeGroupIds>com.oracle.java</includeGroupIds>
<includeTypes>tgz</includeTypes>
<includeArtifactIds>jre</includeArtifactIds>
<includeClassifiers>win32</includeClassifiers>
<outputDirectory>target/win32</outputDirectory>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<!-- This calls launch4j to create the program EXE -->
<groupId>com.akathist.maven.plugins.launch4j</groupId>
<artifactId>launch4j-maven-plugin</artifactId>
<executions>
<execution>
<id>l4j-clui</id>
<phase>package</phase>
<goals>
<goal>launch4j</goal>
</goals>
<configuration>
<headerType>console</headerType>
<outfile>target/encc.exe</outfile>
<jar>target/mavenproject1-1.0-SNAPSHOT.jar</jar>
<errTitle>encc</errTitle>
<classPath>
<mainClass>com.akathist.encc.Clui</mainClass>
<addDependencies>false</addDependencies>
<preCp>anything</preCp>
</classPath>
<jre>
<path>./win32/java</path>
</jre>
<versionInfo>
<fileVersion>1.2.3.4</fileVersion>
<txtFileVersion>txt file version?</txtFileVersion>
<fileDescription>a description</fileDescription>
<copyright>my copyright</copyright>
<productVersion>4.3.2.1</productVersion>
<txtProductVersion>txt product version</txtProductVersion>
<productName>E-N-C-C</productName>
<internalName>ccne</internalName>
<originalFilename>original.exe</originalFilename>
</versionInfo>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
更新3:可悲的事实是,您所需的JRE不存在官方甚至最新的maven回购。您可以托管自己的具有所需JRE的maven仓库。新版本完成后,您必须更新此更新。在发布之前使用新版本进行测试也是一个好主意。每个月的第三个星期二是新Java发布完成的时间。您可以为此设置提醒,以检查是否已发布新版本并下载。由于许可协议检查,自动化这是一个痛苦。这篇文章可能有所帮助,但您可能无法以这种方式下载JRE的tar.gz版本:Java check latest version programmatically
如果您想支持多个平台,那么托管您自己的maven repo是一个很好的方法。每次发布版本时,您都可以托管自己的仓库并使用新的JRE tar.gz进行更新:https://stackoverflow.com/a/29261502/35264
最简单的选择是完成您的目标,只使用您正在构建的JRE。只要使用32位JRE构建,这将允许您支持Windows 32和64。您可以随时更新此版本,因为您有时间使用新版本进行测试。这是一个有效的pom.xml:
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.akathist.encc</groupId>
<artifactId>mavenproject1</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>jar</packaging>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<maven.compiler.source>1.8</maven.compiler.source>
<maven.compiler.target>1.8</maven.compiler.target>
</properties>
<build>
<plugins>
<plugin>
<!-- This copies the JRE used to do the build from java.home - should be 32 bit Windows JRE -->
<artifactId>maven-resources-plugin</artifactId>
<version>2.6</version>
<executions>
<execution>
<id>copy-resources</id>
<!-- here the phase you need -->
<phase>package</phase>
<goals>
<goal>copy-resources</goal>
</goals>
<configuration>
<outputDirectory>${basedir}/target/win32/java</outputDirectory>
<resources>
<resource>
<directory>${java.home}</directory>
</resource>
</resources>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<!-- This calls launch4j to create the program EXE -->
<groupId>com.akathist.maven.plugins.launch4j</groupId>
<artifactId>launch4j-maven-plugin</artifactId>
<executions>
<execution>
<id>l4j-clui</id>
<phase>package</phase>
<goals>
<goal>launch4j</goal>
</goals>
<configuration>
<headerType>console</headerType>
<outfile>target/encc.exe</outfile>
<jar>target/mavenproject1-1.0-SNAPSHOT.jar</jar>
<errTitle>encc</errTitle>
<classPath>
<mainClass>com.akathist.encc.Clui</mainClass>
<addDependencies>false</addDependencies>
<preCp>anything</preCp>
</classPath>
<jre>
<path>./win32/java</path>
</jre>
<versionInfo>
<fileVersion>1.2.3.4</fileVersion>
<txtFileVersion>txt file version?</txtFileVersion>
<fileDescription>a description</fileDescription>
<copyright>my copyright</copyright>
<productVersion>4.3.2.1</productVersion>
<txtProductVersion>txt product version</txtProductVersion>
<productName>E-N-C-C</productName>
<internalName>ccne</internalName>
<originalFilename>original.exe</originalFilename>
</versionInfo>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
答案 1 :(得分:-1)
我相信这就是你要找的东西:
<plugin>
<groupId>com.akathist.maven.plugins.launch4j</groupId>
<artifactId>launch4j-maven-plugin</artifactId>
<executions>
<execution>
...
<configuration>
...
<jre>
<path>${java.home}</path> <!-- SEE THIS -->
</jre>
...
</configuration>
</execution>
</executions>
</plugin>
Java允许您使用java.home
系统属性访问JRE路径。你可以access java system properties within pom。你有一个包装launch4j的插件。将所有这些放在一起,你就有了解决方案。