我有类似的问题,例如How to upload a bytes image on Google Cloud Storage from a Python script。
我试过这个
from google.cloud import storage
import cv2
from tempfile import TemporaryFile
import google.auth
credentials, project = google.auth.default()
client = storage.Client()
# https://console.cloud.google.com/storage/browser/[bucket-id]/
bucket = client.get_bucket('document')
# Then do other things...
image=cv2.imread('/Users/santhoshdc/Documents/Realtest/15.jpg')
with TemporaryFile() as gcs_image:
image.tofile(gcs_image)
blob = bucket.get_blob(gcs_image)
print(blob.download_as_string())
blob.upload_from_string('New contents!')
blob2 = bucket.blob('document/operations/15.png')
blob2.upload_from_filename(filename='gcs_image')
这是错误的错误
> Traceback (most recent call last): File
> "/Users/santhoshdc/Documents/ImageShapeSize/imageGcloudStorageUpload.py",
> line 13, in <module>
> blob = bucket.get_blob(gcs_image) File "/Users/santhoshdc/.virtualenvs/test/lib/python3.6/site-packages/google/cloud/storage/bucket.py",
> line 388, in get_blob
> **kwargs) File "/Users/santhoshdc/.virtualenvs/test/lib/python3.6/site-packages/google/cloud/storage/blob.py",
> line 151, in __init__
> name = _bytes_to_unicode(name) File "/Users/santhoshdc/.virtualenvs/test/lib/python3.6/site-packages/google/cloud/_helpers.py",
> line 377, in _bytes_to_unicode
> raise ValueError('%r could not be converted to unicode' % (value,)) ValueError: <_io.BufferedRandom name=7> could not be
> converted to unicode
任何人都可以指导我出错或者我做错了什么吗?
答案 0 :(得分:2)
根据@ A.Queue in的建议(29天后删除)
from google.cloud import storage
import cv2
from tempfile import TemporaryFile
client = storage.Client()
bucket = client.get_bucket('test-bucket')
image=cv2.imread('example.jpg')
with TemporaryFile() as gcs_image:
image.tofile(gcs_image)
gcs_image.seek(0)
blob = bucket.blob('example.jpg')
blob.upload_from_file(gcs_image)
文件已上传,但上传numpy ndarray
并未保存为google-cloud-storage
PS:
numpy array
必须在保存之前转换为任何图片格式。
这很简单,使用创建的tempfile
来存储图片,这里是代码。
with NamedTemporaryFile() as temp:
#Extract name to the temp file
iName = "".join([str(temp.name),".jpg"])
#Save image to temp file
cv2.imwrite(iName,duplicate_image)
#Storing the image temp file inside the bucket
blob = bucket.blob('ImageTest/Example1.jpg')
blob.upload_from_filename(iName,content_type='image/jpeg')
#Get the public_url of the saved image
url = blob.public_url
答案 1 :(得分:1)
你正在呼叫blob = bucket.get_blob(gcs_image)
,这没有任何意义。 get_blob()
应该得到一个字符串参数,即您想要获取的blob的名称。 名称。但是你传递了一个文件对象。
我建议这段代码:
with TemporaryFile() as gcs_image:
image.tofile(gcs_image)
gcs_image.seek(0)
blob = bucket.blob('documentation-screenshots/operations/15.png')
blob.upload_from_file(gcs_image)