Question

我希望接受用户输入为是/否，如果用户输入是，代码将继续运行可用代码，用户输入否，代码将再次通知用户，代码将不会运行，直到用户输入'是'终于

以下是简要介绍：

# Here is part1 of code


a = input('Have you finished operation?(Y/N)')

if a.lower()  == {'yes','y' }
    # user input 'y', run part2 code

if a.lower() == {'no', 'n'}
    # user input no
    # code should notifying user again "'Have you finished operation?(Y/N)'"  
    # part2 code will run until user finally input 'y'

if a.lower() !={'yes','y', 'no', 'n'}:
    # user input other words
    # code should notifying user again "'Have you finished operation?(Y/N)'" 


# here is part2 of code

您对如何解决此问题有任何想法，如果您能提供一些建议我将不胜感激

更新

这是我正在使用的代码

yes = {'yes','y',}
no = {'no','n'}

print(1)
print(2)
while True:
a = input('Have you create ''manually_selected_stopwords.txt'' ???(Y/N)''')
if a.lower().split() == yes:
    break
if a.lower().split() == no:
    continue

print(3)
print(4)

当我运行它时，它显示如下，我第一次尝试输入'n'然后'y'，这将始终通知我，即使我键入'y'并且不会打印3和4

1
2
Have you create manually_selected_stopwords.txt ???(Y/N)>? n
Have you create manually_selected_stopwords.txt ???(Y/N)>? y
Have you create manually_selected_stopwords.txt ???(Y/N)>? y
Have you create manually_selected_stopwords.txt ???(Y/N)>? y
Have you create manually_selected_stopwords.txt ???(Y/N)

Answer 1

您的一些测试是不必要的。如果输入“no”键入“marmalade”，则会得到相同的结果。

# Here is part1 of code

while True:
    # Calling `.lower()` here so we don't keep calling it
    a = input('Have you finished operation?(Y/N)').lower()

    if a == 'yes' or a == 'y':
        # user input 'y', run part2 code
        break


# here is part2 of code
print('part 2')

编辑：

如果您想使用set而不是or，那么您可以执行以下操作：

if a in {'yes', 'y'}:

Answer 2

您正在比较input()（字符串）的结果与set字符串的相等性。他们永远不平等。

您可以使用in检查输入是否在集合中：

链接的欺骗asking-the-user-for-input-until-they-give-a-valid-response适用于您的问题：

# do part one
yes = {"y","yes"}
no = {"n","no"}

print("Doing part 1")
while True:
    try:
        done = input("Done yet? [yes/no]")
    except EOFError:
        print("Sorry, I didn't understand that.")
        continue

    if done.strip().lower() in yes:
        break # leave while
    elif done.strip().lower() in no:
        # do part one again
        print("Doing part 1")
        pass
    else:    
        # neither yes nor no, back to question
        print("Sorry, I didn't understand that.")

print("Doing part 2")

输出：

Doing part 1
Done yet? [yes/no]  # adsgfsa
Sorry, I did not understand that.
Done yet? [yes/no]  # sdgsdfg
Sorry, I did not understand that.
Done yet? [yes/no]  # 23452345
Sorry, I did not understand that.
Done yet? [yes/no]  # sdfgdsfg
Sorry, I did not understand that.
Done yet? [yes/no]  # no
Doing part 1
Done yet? [yes/no]  # yes
Doing part 2

我如何接受用户的是/否输入，如果他们选择不

2 个答案: