Question

我是IOS的新手，我从后端得到了这个回复

Optional([["contact_name": phone, "verified": <null>, "id": 22033, "entity_id": 1111, "verification_data": <null>, "entity": Recruiter, "view_scope": <null>, "contact_value": 0987654321]])

我需要＆＃34; contact_value＆＃34;来自object的字符串。我怎么得到？

Answer 1

而不是正常的for循环，try map concept。 注意：这是经过测试的代码。

let arrayOfDict: [[String: Any]] = [["contact_name": "phone", "verified": "", "id": 22033, "entity_id": 1111, "verification_data": "", "entity": "Recruiter", "view_scope": "", "contact_value": 0987654321]]

let arraOfCtcName : [Int] = arrayOfDict.map({ (element) in
            let value = element["contact_value"]
            return (value != nil && value is Int) ? value as! Int : 0
        })

Answer 2

let array: [[String: Any]] = [["contact_name": "John", "verified": true, "id": 22033, "entity_id": 1111, "verification_data": "", "entity": "Recruiter", "view_scope": "", "contact_value": 0987654321]]

for item in array {
    let contactName = item["contact_name"] as? String
    print(contactName ?? 0)
}

这只是提取数据的基本/循环，但是根据代码的实现方式，有很多更好的方法可以完成这些工作。

Answer 3

如果您想要的只是contact_value，

，您可以更加实用

let contactValues = a.flatMap { $0 }?
    .map { $0["contact_value"] ?? 0 } as? [Int]

Answer 4

let arrayOfDict: [[[String: Any]] = ["contact_name": "phone", "verified": <null value>, "id": 22033, "entity_id": 1111, "verification_data": <null value>, "entity": "Recruiter", "view_scope": <null value>, "contact_value": 0987654321], ....]

var arrayContact = [Any]()

for dict in arrayOfDict {

  if let contactValue = dict["contact_value"] as? String { //as String
    arrayContact.append(contactValue)
  } else if let contactValue = dict["contact_value"] as? Int { //as Int
    arrayContact.append(contactValue)
  }
}

print(arrayContact)

Answer 5

let array: [[String: Any]] = [["contact_name": "John", "verified": true, "id": 22033, "entity_id": 1111, "verification_data": "", "entity": "Recruiter", "view_scope": "", "contact_value": 0987654321]]

print(array)

for item in array {
    if item["contact_value"] != nil {
        let contact_value = String(describing: item["contact_value"])
        print(contact_value)
        break
    }
}

Answer 6

可选（[[＆＃34; contact_name＆＃34 ;: phone，＆＃34;已验证＆＃34;：，＆＃34; id＆＃34;：22033，＆＃34; entity_id＆＃34;：1111，＆＃34; verification_data＆＃34;：，＆＃34; entity＆＃34 ;: Recruiter，＆＃34; view_scope＆＃34;：，＆＃34; contact_value＆＃34;：0987654321]]）

var string = Optional.toString（）

如何从数组对象中获取字符串

6 个答案: