Question

我正在尝试配置一个Android项目，将多个产品口味与风味尺寸相结合。

以下是build.gradle的片段

android {
    ...
    flavorDimensions "vendor", "type"
    productFlavors {

        development {
            dimension "vendor"
        }

        production {
            dimension "vendor"
        }

        free {
            dimension "type"
        }

        paid {
            dimension "type"
        }
    }
    ...
}

我正在使用谷歌服务，我需要拥有google-services.json文件，我希望每个供应商都有一个不同的文件，一个用于开发，另一个用于生产

所以google-services.json中有一个app/src/development而app/src/production中有一个File google-services.json is missing. The Google Services Plugin cannot function without it. Searched Location: <path>/app/src/developmentPaid/debug/google-services.json <path>/app/src/debug/developmentPaid/google-services.json <path>/app/src/developmentPaid/google-services.json <path>/app/src/debug/google-services.json <path>/app/google-services.json。

构建时我收到此错误：

google-services.json

从错误中我需要app/src/developmentFree和app/src/developmentPaid中的app/src/productionFree以及app/src/productionPaid和android中的另一个{。}}。

使用风味尺寸时，是否需要在两个地方都使用相同的文件？

修改

我最终解决了这个问题，为每个合并的productFlavor添加了几个额外的任务。我在android.productFlavors.all { flavor -> if (flavor.dimension == "vendor") { task("copy${flavor.name.capitalize()}GoogleServicesFile", type: Copy) { description = 'Switches to google-services.json depending on flavor' from "src/${flavor.name}" include "google-services.json" into "." } task("delete${flavor.name.capitalize()}GoogleServicesFile", type: Delete) { description = 'Delete google-services.json from base folder' delete "./google-services.json" } } } android.applicationVariants.all { variant -> def buildType = variant.buildType.name.capitalize() def typeFlavorName = variant.productFlavors.get(0).name.capitalize() def vendorFlavorName = variant.productFlavors.get(1).name.capitalize() def copyFileTaskName = "copy${vendorFlavorName}GoogleServicesFile" def deleteFileTaskName = "delete${vendorFlavorName}GoogleServicesFile" def processGoogleServicesTaskName = "process${typeFlavorName}${vendorFlavorName}${buildType}GoogleServices" tasks."${processGoogleServicesTaskName}".dependsOn "${copyFileTaskName}" tasks."${processGoogleServicesTaskName}".finalizedBy "${deleteFileTaskName}" }之后添加了此代码：

afterEvaluate {

typeFlavorName

}

这样，对于每个vendorFlavorName，buildType和google-services.json变体，app/文件会在process{typeFlavorName}{vendorFlavorName}{buildType}GoogleServices之前复制到union A { int a:1; int b:2; int c1:29; int a:1; int b:2; int c2:28; int d:1; int val; };并删除之后。

Answer 1

最后，我为每个合并后的productFlavor额外解决了两个问题。我在android之后添加了此代码：

afterEvaluate {

    android.productFlavors.all { flavor ->
        if (flavor.dimension == "vendor") {
            task("copy${flavor.name.capitalize()}GoogleServicesFile", type: Copy) {
                description = 'Switches to google-services.json depending on flavor' from "src/${flavor.name}"
                include "google-services.json" into "."
            }
            task("delete${flavor.name.capitalize()}GoogleServicesFile", type: Delete) {
                description = 'Delete google-services.json from base folder'
                delete "./google-services.json"
            }
        }
    }

    android.applicationVariants.all { variant ->
        def buildType = variant.buildType.name.capitalize()
        def typeFlavorName = variant.productFlavors.get(0).name.capitalize()
        def vendorFlavorName = variant.productFlavors.get(1).name.capitalize()
        def copyFileTaskName = "copy${vendorFlavorName}GoogleServicesFile"
        def deleteFileTaskName = "delete${vendorFlavorName}GoogleServicesFile"
        def processGoogleServicesTaskName = "process${typeFlavorName}${vendorFlavorName}${buildType}GoogleServices"
        tasks."${processGoogleServicesTaskName}".dependsOn "${copyFileTaskName}"
        tasks."${processGoogleServicesTaskName}".finalizedBy "${deleteFileTaskName}"
    }
}

通过这种方式，对于每个typeFlavorName，vendorFlavorName和buildType，google-services.json文件在app/之前被复制到process{typeFlavorName}{vendorFlavorName}{buildType}GoogleServices并被删除之后。

将多种产品口味与风味维度

1 个答案: