Question

来自 future import print_function import json import boto3
导入时间导入urllib打印（'加载功能'） s3 = boto3.client（'s3'）

   def lambda_handler(event, context):
  bucket = event['Records'][0]['s3']['bucket']['name']
  key = urllib.unquote_plus(event['Records'][0]['s3']['object']['key'])
  try:
      print("Using waiter to waiting for object to persist thru s3 service")
      waiter = s3.get_waiter('object_exists')
      waiter.wait(Bucket+bucket, Key=key)
      response = s3.head_object(Bucket=bucket, Key=key)
      print("CONTENT TYPE: " +response['ContentType'])
      print("Etag: " + response['ETag'])
      print("Content-Length: ", response['ContentLength'])
      print("Keyname: "+key)
      print("Deleting object" + key)
      s3.delete_object(Bucket=bucket, Key=key)
      return response['ContentType']
   except Exception as e
       print(e)
       print('Error getting object{} from bucket {} . Make sure they exist'
       'bucket is in same region as this is'
       'function.' ,format(key, bucket))
       raise e

Answer 1

您的缩进不正确，就像异常所说的那样。

def lambda_handler(event, context):
   # indented by 3 spaces
   try:
       ...
    # indented by 4 spaces ... 
    except Exception as e  # NOTE: Missing `:`
        ...

您的代码示例在异常处理程序的末尾也缺少:

Answer 2

就在这里：

           print("Content-Length: ", response['ContentLength'])
           print("Keyname: "+key)
           print("Deleting object" + key)
           s3.delete_object(Bucket=bucket, Key=key)
           return response['ContentType']
        except Exception as e: #<---also add me, the colon :)
            print(e)
            print('Error getting object{} from bucket {} . Make sure they exist'
            'bucket is in same region as this is'
            'function.' ,format(key, bucket))
            raise e

除了需要移回一个空格之外的东西的缩进。

模块'lambda_function'中的语法错误：unindent与任何外部缩进级别都不匹配（lambda_function.py，第26行）

2 个答案: