我的SQL查询在 MariaDB CLI中有效,但在python pymysql 中无效。
我想获取具有相同用户名的记录编号( COUNT(*)),然后为每个用户获取排名(rowNo),如果是用户名具有相同的记录( COUNT(*)),等级(rowNo)也相同(@rowNo:= @ rowNo)。
在SQL下 MariaDB CLI中,相同数量的记录具有相同的排名(rowNo)。但是在python pymysql中,相同数量的reocord有不同的等级(rowNO),它会增加(@rowNo:= @ rowNo + 1)。为什么呢?
art_sql = "SELECT T2.rowNo, T2.username, T2.art_number \
FROM \
(SELECT T1.art_number, \
T1.username, \
IF(@c=T1.art_number,@rowNo:=@rowNo,@rowNo:=@rowNo+1) AS rowNo, \
@c:=T1.art_number \
FROM \
( \
SELECT username,COUNT(*) AS art_number \
FROM %s \
GROUP BY username \
ORDER BY art_number DESC \
)T1 \
)T2, (SELECT @rowNo:=0,@c:=0)T3 \
WHERE T2.username='%s';" \
% (self.__article_table, username)
顺便说一下,我在下面有一个类似的SQL没有这个问题:
rev_sql = "SELECT T2.rowNo, T2.username, T2.total_revenue \
FROM \
(SELECT T1.total_revenue, \
T1.username, \
IF(@c=T1.total_revenue,@rowNo:=@rowNo,@rowNo:=@rowNo+1) AS rowNo, \
@c:=T1.total_revenue \
FROM \
( \
SELECT username,SUM(money) AS total_revenue \
FROM %s \
GROUP BY username \
ORDER BY total_revenue DESC \
)T1 \
)T2, (SELECT @rowNo:=0,@c:=0)T3 \
WHERE username='%s';" \
% (self.__article_table, username)
你能帮忙解答一下吗?感谢〜
答案 0 :(得分:0)
IF(@ c = T1.total_revenue,@ rowNo:= @ rowNo,@ rowNo:= @ rowNo + 1)AS行号,\ @c:= T1.total_revenue 尝试 IF(@ c = T1.total_revenue,@ rowNo:= @ rowNo,@ rowNo:= @ rowNo + 1)AS行号,\ (@c:= T1.total_revenue)