Question

我想将上传的图片文件名更改为某个名称，例如：
Original name:city.jpg -> D0000_04042018094730121.jpg
（D0000是kodeDosen，另一个是microtime时间戳。）
这是我的php代码：
uploadDosen.php

 <?php
  include 'connectdb.php';

  if (isset($_POST['upload_Btn'])) {
    $target = "uploaddosen/".basename($_FILES['gambar']['name']);
    $kodeDosen = $_POST['kodeDosen'];
    $namaJurnal = $_POST['namaJurnal'];
    $tipePublikasi = $_POST['tipePublikasi'];
    $status= $_POST['status'];
    $gambar = $_FILES['gambar']['name'];


    $sql = "INSERT INTO tbl_publikasi (kodeDosen,gambar,namaJurnal,tipePublikasi,status) VALUES ('$kodeDosen','$gambar','$namaJurnal',
    '$tipePublikasi','$status')";
    // execute query
    mysqli_query($conn, $sql);

    if (move_uploaded_file($_FILES['gambar']['tmp_name'],$target)) {
        $msg = "Image uploaded successfully";
    }else{
        $msg = "Failed to upload image";
    }

    header("location:uploadTest.php");
    }




   ?>

Answer 1

只需将 $ target 的值更改为首选文件名即可。

您可以尝试：

$extention = explode(".", $_FILES['gambar']['name']);
$extention = end($extention);
$target = $kodeDosen."_".str_replace(array(".", " "), "", microtime() ).".".$extention;

Answer 2

而不是使用

$target = "uploaddosen/".basename($_FILES['gambar']['name']);

将您想要的名字放在

中

$ext = end((explode(".", $_FILES['gambar']['name'])));
$target = "uploaddosen/MYNEWNAME." . $ext

$ ext正在获取上传的文件名并获取文件扩展名。然后将它与您的新名称一起添加。

将php图像上传文件名更改为特定名称

2 个答案: