Question

我是一名编码新手，他对如何使这个程序工作感到困惑和困惑。

显示菜单以显示不同的数据计划。计划1每月39.99美元，包括450分钟。额外的分钟是每分钟0.45美元。计划2每月59.99美元，900分钟。额外的分钟是每分钟0.40美元。计划3每月69.99美元，无限制分钟。

•客户的帐号 •客户的计划编号• 客户使用的总分钟数 •应付总金额（格式化）

输入验证：确保用户仅选择包1,2或3。

我使用三种不同的搜索查询变体搜索了stackoverflow：＆＃39;数据计划＆＃39;手机数据计划＆＃39;如何计算数据计划＆＃39;我确实找到了这篇文章Comparing Cell Phone Plans in C++，这是一个有点类似的程序，但不够相似。我也搜索了它，发现了一些类似的程序，但它们更有帮助，但是太复杂，对我没有足够的帮助。

我处于停滞状态，并且不知道如何使用计划一和计划二上使用的分钟数来计算总账单，这些分钟超过了这两个计划的分配时间。

这是我到目前为止所拥有的：

let jsonString = "{\"boolean_key\" : true, \"int_key\" : 1}"
let jsonData = jsonString.data(using: .utf8)!
let json = try! JSONSerialization.jsonObject(with: jsonData, options: []) as! [String:Any]

print(type(of: json["boolean_key"]!)) // __NSCFBoolean
json["boolean_key"] is Double // true
json["boolean_key"] is Int // true
json["boolean_key"] is Bool // true

print(type(of: json["int_key"]!)) // __NSCFNumber
json["int_key"] is Double // true
json["int_key"] is Int // true
json["int_key"] is Bool // true

print(type(of: json["boolean_key"]!) == type(of: NSNumber(value: true))) // true
print(type(of: json["boolean_key"]!) == type(of: NSNumber(value: 1))) // false
print(type(of: json["int_key"]!) == type(of: NSNumber(value: 0))) // true
print(type(of: json["int_key"]!) == type(of: NSNumber(value: true))) // false

Answer 1

以下是如何根据使用的分钟计算每个计划的成本的示例。

我使用0分钟以每分钟0的成本代表无限分钟，因为它使数学变得容易，并使用函数返回那些分钟的显示值，因此0 =“无限制”。

#include <iostream>
#include <string>

double calculateCost(double planCost, 
    double minuteCost, 
    int minutesIncluded, 
    int minutesUsed)
{
    double cost = planCost;
    int overage = minutesUsed - minutesIncluded;
    if (overage > 0)
    {
        cost += minuteCost * overage;
    }
    return cost;
}

std::string includedMinutesString(int numMinutes)
{
    if (numMinutes > 0)
    {
        return std::to_string(numMinutes);
    }
    return "unlimited";
}

int main()
{
    {
        double planCost = 39.99;
        double minuteCost = 0.45;
        int minutesIncluded = 450;
        int minutesUsed = 1000;
        std::cout << "Plan Cost: " << planCost << " with " << 
            includedMinutesString(minutesIncluded) << " minutes included\n";
        std::cout << "Cost with " << minutesUsed << " minutes used is  " << 
            calculateCost(planCost, minuteCost, minutesIncluded, minutesUsed) << "\n";
    }
    std::cout << "\n";
    {
        double planCost = 59.99;
        double minuteCost = 0.40;
        int minutesIncluded = 900;
        int minutesUsed = 1000;
        std::cout << "Plan Cost: " << planCost << " with " << 
            includedMinutesString(minutesIncluded) << " minutes included\n";
        std::cout << "Cost with " << minutesUsed << " minutes used is  " << 
            calculateCost(planCost, minuteCost, minutesIncluded, minutesUsed) << "\n";
    }
    std::cout << "\n";
    {
        double planCost = 69.99;
        double minuteCost = 0;
        int minutesIncluded = 0;
        int minutesUsed = 1000;
        std::cout << "Plan Cost: " << planCost << " with " << 
            includedMinutesString(minutesIncluded) << " minutes included\n";
        std::cout << "Cost with " << minutesUsed << " minutes used is  " << 
            calculateCost(planCost, minuteCost, minutesIncluded, minutesUsed) << "\n";
    }
    return 0;
}

我可以获得有关如何在计算数据计划时修复此C ++程序的任何建议吗？

1 个答案: