Question

情况：

一次更新5个表（表1，表2，表3，表4，表5）。所有表都有“title_galery”和“uid_galery”列。我需要将所有“title_galery”列更新为“新标题”，其中“uid_galery”为“555”。

Ps：列可以是空的，也可以是其他数据，因此，我只需要更新与“uid_galery”匹配的行。

我已经尝试了JOIN和INNER JOIN而没有成功。

更新

最后的尝试：

$conecta_for_003 = "UPDATE";
$conecta_for_003 .= "  table1";
$conecta_for_003 .= "  INNER JOIN table2 ON table2.uid_galery=table1.uid_galery";
$conecta_for_003 .= "  INNER JOIN table3 ON table3.uid_galery=table1.uid_galery";
$conecta_for_003 .= "  INNER JOIN table4 ON table4.uid_galery=table1.uid_galery";

$conecta_for_003 .= " SET";
$conecta_for_003 .= "  table1.title_galery='New Title'";
$conecta_for_003 .= ", table2.title_galery='New Title'";
$conecta_for_003 .= ", table3.title_galery='New Title'";
$conecta_for_003 .= ", table4.title_galery='New Title'";
$conecta_for_003 .= " WHERE";
$conecta_for_003 .= "  table1.uid_galery='555'";

Answer 1

此尝试仅适用于2张桌子。

$conecta_for_003 = "UPDATE";
$conecta_for_003 .= "  table1";
$conecta_for_003 .= ", table2";
$conecta_for_003 .= " SET";
$conecta_for_003 .= "  table1.title_galery='New Title'";
$conecta_for_003 .= ", table2.title_galery='New Title'";
$conecta_for_003 .= " WHERE";
$conecta_for_003 .= " table2.uid_galery = table1.uid_galery";
$conecta_for_003 .= " AND";
$conecta_for_003 .= "  table1.uid_galery='555'";

我试图改变它，但没有尝试过。

一次更新5个表。相同列

1 个答案: