所以我试图在Next.js应用程序的客户端上拼接多个远程GraphCMS端点,在尝试/组合互联网上的每个示例之后,我已经得到了它一个值得询问的地方。我的错误:
TypeError: this.getClient(...).watchQuery is not a function at GraphQL.createQuery
github repo here ,您可以在上下文中看到此initApollo.js:
import { ApolloClient } from 'apollo-client'
import {
makeRemoteExecutableSchema,
mergeSchemas,
introspectSchema
} from 'graphql-tools'
import { HttpLink } from 'apollo-link-http'
import { InMemoryCache } from 'apollo-cache-inmemory'
import fetch from 'node-fetch'
import { Observable, ApolloLink } from 'apollo-link'
import { graphql, print } from 'graphql'
import { createApolloFetch } from 'apollo-fetch'
let apolloClient = null
if (!process.browser) {
global.fetch = fetch
}
const PRIMARY_API = 'https://api.graphcms.com/simple/v1/cjfipt3m23x9i0190pgetwf8c'
const SECONDARY_API = 'https://api.graphcms.com/simple/v1/cjfipwwve7vl901427mf2vkog'
const ALL_ENDPOINTS = [PRIMARY_API, SECONDARY_API]
async function createClient (initialState) {
const AllLinks = ALL_ENDPOINTS.map(endpoint => {
return new HttpLink({
uri: endpoint,
fetch
})
})
const allSchemas = []
for (let link of AllLinks) {
try {
allSchemas.push(
makeRemoteExecutableSchema({
schema: await introspectSchema(link),
link
})
)
} catch (e) {
console.log(e)
}
}
const mergedSchema = mergeSchemas({
schemas: allSchemas
})
const mergedLink = operation => {
return new Observable(observer => {
const { query, variables, operationName } = operation
graphql(mergedSchema, print(query), {}, {}, variables, operationName)
.then(result => {
observer.next(result)
observer.complete()
})
.catch(e => observer.error(e))
})
}
return new ApolloClient({
connectToDevTools: process.browser,
ssrMode: !process.browser,
link: mergedLink,
cache: new InMemoryCache().restore(initialState || {})
})
}
export default function initApollo (initialState) {
if (!process.browser) {
return createClient(initialState)
}
if (!apolloClient) {
apolloClient = createClient(initialState)
}
console.log('\x1b[37m%s\x1b[0m', apolloClient)
return apolloClient
}
我在.then()
内Observable
内获取有用数据,我可以在result
中记录=DIVIDE($A1,5)