Question

首先，我运行此查询，创建一个表并插入两行数据。

declare @data table (date varchar(10),x1 int,x2 int,x3 int,y1 int,y2 int,y3 int,z1  numeric(5,2),z2  numeric(5,2),z3 numeric(5,2))

insert into @data values ('2017-05-15',11,12,15,21,31,41,0.1,0.4,0.5)

insert into @data values ('2017-05-16',11,12,15,21,31,41,0.1,0.4,0.5)

然后我运行此查询来转换表中的行：

select date,x1 as 'a1',y1 as 'b1', z1 as 'c1' from @data    
union all     
select date,x2 as 'a2',y2 as 'b2', z2 as 'c2' from @data    
union all    
select date,x3 as 'a3',y3 as 'b3', z3 as 'c3' from @data    
order by date

我得到了这个结果

2017-05-15  11  21  0.10
2017-05-15  12  31  0.40
2017-05-15  15  41  0.50
2017-05-16  15  41  0.50
2017-05-16  12  31  0.40
2017-05-16  11  21  0.10

第一个表（前3行）正在生成OK，第二个表正在反转。然后第3个也好了等等......

请尝试运行此查询以了解我的意思。

KBV。

Answer 1

我认为您正在尝试显示存储为行的3x3矩阵。如果是这种情况，那么您可以在每个矩阵行中添加一个硬编码的数字，并在日期之后按该数字排序：

select 1 as ordernumber, date,x1 as 'a1',y1 as 'b1', z1 as 'c1' from @data

union all

select 2 as ordernumber, date,x2 as 'a2',y2 as 'b2', z2 as 'c2' from @data

union all

select 3 as ordernumber, date,x3 as 'a3',y3 as 'b3', z3 as 'c3' from @data

order by date, ordernumber

如果您不想显示该号码，请使用子查询：

SELECT
    date,
    a1,
    b1,
    c1
FROM
(
    select 1 as ordernumber, date,x1 as 'a1',y1 as 'b1', z1 as 'c1' from @data

    union all

    select 2 as ordernumber, date,x2 as 'a2',y2 as 'b2', z2 as 'c2' from @data

    union all

    select 3 as ordernumber, date,x3 as 'a3',y3 as 'b3', z3 as 'c3' from @data
) AS T
order by 
    date, 
    ordernumber

sql union所有指令问题

1 个答案: