广播接收器读取来电者的姓名

Question

我正在尝试让应用程序读出来电者的姓名。我认为注册BroadcastReceiver的方式存在问题，但没有显示错误。

        private void initializeCallReceiver(){
    callReceiver = new BroadcastReceiver(){
@Override
        public void onReceive(Context context, Intent intent) {
            if(intent.getStringExtra(TelephonyManager.EXTRA_STATE).equals(TelephonyManager.EXTRA_STATE_RINGING)){
                String caller = intent.getStringExtra(TelephonyManager.EXTRA_INCOMING_NUMBER);
                speaker.speak("Call from " + caller);
            }
        }
    };

}

 private void registerCallReceiver() {
    IntentFilter intentFilter = new IntentFilter("android.provider.Telephony.EXTRA_STATE_RINGING");
    registerReceiver(callReceiver,intentFilter);
}

Oncreate方法

 toggle = (ToggleButton)findViewById(R.id.speechToggle);
    smsText = (TextView)findViewById(R.id.sms_text);
    smsSender = (TextView)findViewById(R.id.sms_sender);



    toggleListener = new CompoundButton.OnCheckedChangeListener() {
        @Override
        public void onCheckedChanged(CompoundButton view, boolean isChecked) {
            if(isChecked){
                speaker.allow(true);
                speaker.speak(getString(R.string.start_speaking));
            }else{
                speaker.speak(getString(R.string.stop_speaking));
                speaker.allow(false);
            }
        }
    };
    toggle.setOnCheckedChangeListener(toggleListener);

    checkTTS();
    initializeCallReceiver();
    registerCallReceiver();

}

Answer 1

这是我得到的解决方案。它现在有效。
 private void registerCallReceiver（）{         IntentFilter intentFilter = new IntentFilter（“android.intent.action.PHONE_STATE”）;         registerReceiver（callReceiver，IntentFilter的）;