Question

我正在尝试在Tornado中初始化my_object实例时传递WebSocketHandler的实例作为参数，因此我可以在通信期间使用它。我试图做以下但没有成功。

class WSWebHandler(tornado.websocket.WebSocketHandler):
    def __init__(self, my_object):
        super(tornado.websocket.WebSocketHandler, self).__init__()
        self.my_object = my_object

    def open(self):
        print('new connection')

    def on_message(self, message):
        print('message received: %s' % message)

    def on_close(self):
        print('connection closed')

    def check_origin(self, origin):
        return True

my_object = new My_Object()

application = tornado.web.Application([(r'/ws', WSWebHandler), my_object])
http_server = tornado.httpserver.HTTPServer(application)
http_server.listen(8080)
myIP = socket.gethostbyname(socket.gethostname())
print ('*** Websocket Server Started at %s***' % myIP)
tornado.ioloop.IOLoop.instance().start()

我猜错了哪里？

提前致谢

Answer 1

Tornado提供了一种将参数传递给处理程序的不同机制。在处理程序类中创建一个名为initialize的方法。 Tornado将使用您的自定义参数自动调用此方法：

class WSWebHandler(tornado.websocket.WebSocketHandler):
    def initialize(self, my_object):
        self.my_object = my_object

您也错误地传递了参数。正确的方法是：

tornado.web.Application(
    [
        (r'/ws', WSWebHandler, {'my_object': my_object}),
       # \____/  \__________/  \______________________/
       #   url      handler       dict of extra args

    ],
)

如何将参数传递给Tornado的WebSocketHandler类？

1 个答案: