下面是我的DataSet，Desired Output（使用规则中的DOB规范派生年龄）
需要你的帮助（请注意我在MSSQL环境中寻找解决方案）： -
1. 提出Age字段。（我尝试了以下脚本，但它没有工作，因为它不够动态，不包括所有DOB规则，我还附加了一个有效的oracle脚本作为你们的参考）
SELECT
[ID],
[DOB],
'age' = DATEDIFF(HOUR,(CONVERT(date,(CASE WHEN ([DOB] like '99/%/%') THEN (REPLACE([DOB],'99','01'))
ELSE [DOB] END),103)),GETDATE())/8766
from [Sample]
Sample_Dataset
create table Sample (
Id Varchar (50),
DOB Varchar (50))
insert into Sample(Id, DOB)
Values
('38603', '24/02/1969'),
('38605', '22/09/1969'),
('36356', '17/03/1954'),
('36374', '17/05/1975'),
('36441', '17/08/1961'),
('1a', '10/05/9999'),
('1b', '10/99/9999'),
('1c', '99/99/9999'),
('2a', '--/--/1935'),
('2b', '00/00/1935'),
('2c', '88/88/1935'),
('2d', '99/99/1935'),
('3a', '10/--/1935'),
('3b', '10/00/1935'),
('3c', '10/88/1935'),
('3d', '10/99/1935'),
('4a', '--/09/1935'),
('4b', '00/09/1935'),
('4c', '88/09/1935'),
('4d', '99/09/1935')
所需的输出
ID | DOB | Age (As of 05-03-2018; dd-mm-yyyy) 38603 | 24/02/1969 | 49 --Everything is known 38605 | 22/09/1969 | 48 36356 | 17/03/1954 | 63 36374 | 17/05/1975 | 42 36441 | 17/08/1961 | 56 1a | 10/05/9999 |null --unknown year 1b | 10/99/9999 |null 1c | 99/99/9999 |null 2a | --/--/1935 |82 --unknown day and month 2b | 00/00/1935 |82 2c | 88/88/1935 |82 2d | 99/99/1935 |82 3a | 10/--/1935 |82 --unknown month but known year 3b | 10/00/1935 |82 3c | 10/88/1935 |82 3d | 10/99/1935 |82 4a | --/09/1935 |82 --unknown day but known month 4b | 00/09/1935 |82 4c | 88/09/1935 |82 4d | 99/09/1935 |82
规则： - 正如您在评论
中的上述 5场景中所看到的那样Oracle解决方案
首先创建一个函数（尝试在T-SQL中复制此逻辑但不成功，因此我在这里）
create or replace function check_dt(in_date in VARCHAR2, in_format in VARCHAR2 default 'DD/MM/YYYY')
RETURN NUMBER
IS
V_DATE DATE;
V_STATUS INTEGER;
BEGIN
SELECT TO_DATE(in_date,in_format)
INTO V_DATECASE
FROM DUAL;
V_STATUS := 0;
RETURN V_STATUS;
EXCEPTION WHEN OTHERS THEN
V_STATUS := SQLCODE;
RETURN V_STATUS;
END;
select check_dt('11/30/2017') from dual;
select TO_DATE('15/--/9999','DD/MM/YYYY') from dual;
select id, dob,
case when check_dt(dob) = -1843 --not valid month, default it to July (07)
THEN substr(dob,1,2)||'/07'||substr(dob,7,4)
when check_dt(dob) = -01847 -- day of month must between 1 and last day of month
THEN '1/07/'||substr(dob,7,4)
WHEN check_dt(dob) = 0 and to_date(dob,'dd/mm/yyyy') > sysdate
THEN NULL
WHEN check_dt(dob) = -0183 -- date not valid for month
THEN '15/'||substr(dob,4)
ELSE
THEN dob
END New_dob
from SAMPLE;
非常感谢任何帮助。 非常感谢你。
答案 0 :(得分：2)
SQL SERVER
SELECT id,
CASE WHEN YEAR(GETDATE())-REVERSE(LEFT(REVERSE(DOB), CHARINDEX('/', REVERSE(DOB)) - 1)) > = 0
THEN
YEAR(GETDATE())-REVERSE(LEFT(REVERSE(DOB), CHARINDEX('/', REVERSE(DOB)) - 1))
ELSE
NULL
END AS Age
FROM Sample
您的问题的解决方案
WITH CTE AS
(
SELECT id,
CASE WHEN ISNUMERIC(REVERSE(LEFT(REVERSE(DOB), CHARINDEX('/', REVERSE(DOB)) - 1))) = 1 THEN
REVERSE(LEFT(REVERSE(DOB), CHARINDEX('/', REVERSE(DOB)) - 1))
ELSE
NULL
END
AS Year,
CASE WHEN ISNUMERIC(LEFT(DOB, CHARINDEX('/', DOB) - 1)) = 1 THEN
LEFT(DOB, CHARINDEX('/', DOB) - 1)
ELSE
NULL
END AS DAY,
CASE WHEN ISNUMERIC(SUBSTRING(DOB,CHARINDEX('/',DOB)+1, CHARINDEX('/',DOB,CHARINDEX('/',DOB)+1) -CHARINDEX('/',DOB)-1)) = 1 THEN
CASE WHEN SUBSTRING(DOB,CHARINDEX('/',DOB)+1, CHARINDEX('/',DOB,CHARINDEX('/',DOB)+1) -CHARINDEX('/',DOB)-1) >= 1 AND SUBSTRING(DOB,CHARINDEX('/',DOB)+1, CHARINDEX('/',DOB,CHARINDEX('/',DOB)+1) -CHARINDEX('/',DOB)-1) <= 12 THEN
SUBSTRING(DOB,CHARINDEX('/',DOB)+1, CHARINDEX('/',DOB,CHARINDEX('/',DOB)+1) -CHARINDEX('/',DOB)-1)
ELSE
NULL
END
ELSE
NULL
END AS MONTH
FROM Sample),CTE1 AS
(
SELECT id,
year,
month,
CASE WHEN DAY IS NOT NULL THEN
CASE WHEN DAY >= 1 AND DAY <= DAY(EOMONTH(year+'-'+month+'-01')) THEN
DAY
ELSE
NULL
END
ELSE NULL
END AS Day
FROM CTE
)
,CTE2 AS
(
SELECT id,
CASE WHEN YEAR IS NULL
THEN NULL
ELSE
CASE WHEN DAY IS NULL AND MONTH IS NULL THEN '01/07'
WHEN MONTH IS NULL AND DAY IS NOT NULL THEN CAST(day AS VARCHAR)+'/07'
WHEN MONTH IS NOT NULL AND DAY IS NULL THEN '15/'+CAST(MONTH AS VARCHAR)
ELSE CAST(day AS VARCHAR)+'/'+CAST(MONTH AS VARCHAR)
END
+ '/'+CAST(YEAR AS VARCHAR)
END
AS DOB
FROM CTE1
)
SELECT id,DOB,
CASE WHEN DOB IS NOT NULL
THEN
CASE WHEN DATEDIFF (day, CONVERT(DATE, DOB, 103),CONVERT(DATE,GETDATE(),103)) >=0
THEN FLOOR(DATEDIFF (day, CONVERT(DATE, DOB, 103), CONVERT(DATE,GETDATE(),103)) / 365.2425)
ELSE
NULL
END
ELSE
DOB
END AS Age
FROM CTE2
DEMO LIVE
http://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=3714d33cacb02c3fce4f0868c9d0990b
答案 1 :(得分：1)
您可以使用以下内容。我使用不同的CTE来向您展示从varchar DOB获得出生日期的进展情况。我也把桌子换成了临时桌子。
IF OBJECT_ID('tempdb..#Sample') IS NOT NULL
DROP TABLE #Sample
create table #Sample (
Id Int,
DOB Varchar (50))
insert into #Sample(Id, DOB)
Values
(38603, '24/02/1969'),
(38605, '22/09/1969'),
(36356, '17/03/1954'),
(36374, '17/05/1975'),
(36441, '17/08/1961'),
(119, '10/05/9999'),
(114, '10/99/9999'),
(132, '99/99/9999'),
(25125, '--/--/1935'),
(2323, '00/00/1935'),
(2512, '88/88/1935'),
(2156, '99/99/1935'),
(368, '10/--/1935'),
(34135, '10/00/1935'),
(3435, '10/88/1935'),
(3241, '10/99/1935'),
(4512, '--/09/1935'),
(4161, '00/09/1935'),
(4312, '88/09/1935'),
(456, '99/09/1935')
;WITH ParsedBirth AS
(
SELECT
S.Id,
S.DOB,
Year = SUBSTRING(S.DOB, 7, 4),
Month = SUBSTRING(S.DOB, 4, 2),
Day = SUBSTRING(S.DOB, 1, 2)
FROM
#Sample AS S
),
ParsedBirthInteger AS
(
SELECT
P.Id,
P.DOB,
Year = CASE WHEN ISNUMERIC(P.Year) = 1 AND P.Year <> '9999' THEN CONVERT(INT, P.Year) END,
Month = CASE
WHEN ISNUMERIC(P.Month) = 1 AND CONVERT(INT, P.Month) BETWEEN 1 AND 12 THEN CONVERT(INT, P.Month)
ELSE 7 END,
Day = CASE
WHEN ISNUMERIC(P.Day) = 1 AND CONVERT(INT, P.Day) BETWEEN 1 AND 31 THEN CONVERT(INT, P.Day)
ELSE 15 END
FROM
ParsedBirth AS P
),
InferredBirth AS
(
SELECT
P.Id,
P.DOB,
InferredBirth = CONVERT(DATE, CONVERT(VARCHAR(100), P.Year * 10000 + P.Month * 100 + P.Day))
FROM
ParsedBirthInteger AS P
)
SELECT
T.Id,
T.DOB,
T.InferredBirth,
Age = (CONVERT(INT,CONVERT(char(8), GETDATE(),112))-CONVERT(char(8),T.InferredBirth,112))/10000
FROM
InferredBirth AS T
答案 2 :(得分：0)
首先：
9999含义＆＃34;没有年份＆＃34;）是一个非常糟糕的主意。以下代码会将您的值转换为您应该用来存储它的格式。你可以从这里建立你的年龄逻辑，但我真的建议你，使用这种方法来清理这些混乱并妥善存储你的数据！
DECLARE @sample TABLE(
Id VARCHAR(10),
DOB VARCHAR (50))
INSERT INTO @sample(Id, DOB)
VALUES
('38603', '24/02/1969'),
('38605', '22/09/1969'),
('36356', '17/03/1954'),
('36374', '17/05/1975'),
('36441', '17/08/1961'),
('1a', '10/05/9999'),
('1b', '10/99/9999'),
('1c', '99/99/9999'),
('2a', '--/--/1935'),
('2b', '00/00/1935'),
('2c', '88/88/1935'),
('2d', '99/99/1935'),
('3a', '10/--/1935'),
('3b', '10/00/1935'),
('3c', '10/88/1935'),
('3d', '10/99/1935'),
('4a', '--/09/1935'),
('4b', '00/09/1935'),
('4c', '88/09/1935'),
('4d', '99/09/1935');
- 查询会将您的字符串拆分为/并尝试将值转换为int：
WITH Splitted AS
(
SELECT Id
,DOB
,CAST('<x>' + REPLACE(DOB,'/','</x><x>') + '</x>' AS XML).value('/x[1]','varchar(10)') AS DOB_Day
,CAST('<x>' + REPLACE(DOB,'/','</x><x>') + '</x>' AS XML).value('/x[2]','varchar(10)') AS DOB_Month
,CAST('<x>' + REPLACE(DOB,'/','</x><x>') + '</x>' AS XML).value('/x[3]','varchar(10)') AS DOB_Year
FROM @sample
)
,Casted AS
(
SELECT Id
,DOB
--below SQL-Server 2012 you can use `CASE` with `ISNUMERIC` instead of TRY_CAST
,TRY_CAST(DOB_Day AS INT) AS CastedDay
,TRY_CAST(DOB_Month AS INT) AS CastedMonth
,TRY_CAST(DOB_Year AS INT) AS CastedYear
FROM Splitted
)
,Checked AS
(
SELECT Id
,DOB
--You can use further logic to get the month's days correctly (instead of the plain 31)
,CASE WHEN CastedDay BETWEEN 1 AND 31 THEN CastedDay ELSE NULL END AS TheDay
,CASE WHEN CastedMonth BETWEEN 1 AND 12 THEN CastedMonth ELSE NULL END AS TheMonth
,CASE WHEN CastedYear BETWEEN 1900 AND 2100 THEN CastedYear ELSE NULL END AS TheYear
FROM Casted
)
SELECT *
FROM Checked;
结果
+-------+------------+--------+----------+---------+
| Id | DOB | TheDay | TheMonth | TheYear |
+-------+------------+--------+----------+---------+
| 38603 | 24/02/1969 | 24 | 2 | 1969 |
+-------+------------+--------+----------+---------+
| 38605 | 22/09/1969 | 22 | 9 | 1969 |
+-------+------------+--------+----------+---------+
| 36356 | 17/03/1954 | 17 | 3 | 1954 |
+-------+------------+--------+----------+---------+
| 36374 | 17/05/1975 | 17 | 5 | 1975 |
+-------+------------+--------+----------+---------+
| 36441 | 17/08/1961 | 17 | 8 | 1961 |
+-------+------------+--------+----------+---------+
| 1a | 10/05/9999 | 10 | 5 | NULL |
+-------+------------+--------+----------+---------+
| 1b | 10/99/9999 | 10 | NULL | NULL |
+-------+------------+--------+----------+---------+
| 1c | 99/99/9999 | NULL | NULL | NULL |
+-------+------------+--------+----------+---------+
| 2a | --/--/1935 | NULL | NULL | 1935 |
+-------+------------+--------+----------+---------+
| 2b | 00/00/1935 | NULL | NULL | 1935 |
+-------+------------+--------+----------+---------+
| 2c | 88/88/1935 | NULL | NULL | 1935 |
+-------+------------+--------+----------+---------+
| 2d | 99/99/1935 | NULL | NULL | 1935 |
+-------+------------+--------+----------+---------+
| 3a | 10/--/1935 | 10 | NULL | 1935 |
+-------+------------+--------+----------+---------+
| 3b | 10/00/1935 | 10 | NULL | 1935 |
+-------+------------+--------+----------+---------+
| 3c | 10/88/1935 | 10 | NULL | 1935 |
+-------+------------+--------+----------+---------+
| 3d | 10/99/1935 | 10 | NULL | 1935 |
+-------+------------+--------+----------+---------+
| 4a | --/09/1935 | NULL | 9 | 1935 |
+-------+------------+--------+----------+---------+
| 4b | 00/09/1935 | NULL | 9 | 1935 |
+-------+------------+--------+----------+---------+
| 4c | 88/09/1935 | NULL | 9 | 1935 |
+-------+------------+--------+----------+---------+
| 4d | 99/09/1935 | NULL | 9 | 1935 |
+-------+------------+--------+----------+---------+