这是我使用的代码,但是我确实获得了所有csv文件,但是只有一行包含列名,没有其他数据......你能告诉我我的代码有什么问题吗?
m<-length(unique(rd_1$mall))
dataframe.list<-list()
for(i in 1:m){
dataframe.list[[i]] <- subset(rd_1, mall==i)
write.csv(dataframe.list[[i]], file =
paste0("C:/Users/yogesh/Desktop/Work/Analysis/","mall_",i,
".csv"), row.names = TRUE)
}
这是一个可重复的例子:
y <- length(unique(population$year))
dataframe.list <- list()
for (i in 1:y){
dataframe.list[[i]] <- subset(population, year == i)
write.csv(dataframe.list[[i]], file = paste0("year_", i), row.names = TRUE)
}
read.csv("year_1", row.names = 1)
# [1] country year population
# <0 rows> (or 0-length row.names)
答案 0 :(得分:2)
当您在循环中运行第一行时:
dataframe.list[[i]] <- subset(rd_1, mall == i)
您正在rd_1
中查找mall
的值为1
的行。鉴于你的第一线,我认为这不是你想要的。尝试创建一个新的向量,可以将其命名为malls
。将其设置为unique(rd1$mall)
。然后,在您进行分组时,请使用mall == malls[i]
,而不是mall == i
。
malls <-unique(rd_1$mall)
m <- length(malls)
dataframe.list<-list()
for(i in 1:m){
dataframe.list[[i]] <- subset(rd_1, mall==malls[i])
write.csv(dataframe.list[[i]], file =
paste0("C:/Users/yogesh/Desktop/Work/Analysis/","mall_",i,
".csv"), row.names = TRUE)
}
我们可以使用内置数据集population
重现您的问题和解决方案。请注意,只是改进代码的附注。当您浏览1:m
或1:y
时,您知道要经历多少个对象。分配列表的大小。这是dataframe.list <- vector("list", y)
问题:
y <- length(unique(population$year))
dataframe.list <- vector("list", y)
for (i in 1:y){
dataframe.list[[i]] <- subset(population, year == i)
write.csv(dataframe.list[[i]], file = paste0("year_", i), row.names = TRUE)
}
read.csv("year_1")
[1] X country year population
<0 rows> (or 0-length row.names)
解决方案:
years <- unique(population$year)
y <- length(years)
dataframe.list <- vector("list", y)
for (i in 1:y){
dataframe.list[[i]] <- subset(population, year == years[i])
write.csv(dataframe.list[[i]], file = paste0("year_", i), row.names = TRUE)
}
head(read.csv("year.1", row.names = 1))
country year population
1 Afghanistan 1995 17586073
2 Albania 1995 3357858
3 Algeria 1995 29315463
4 American Samoa 1995 52874
5 Andorra 1995 63854
6 Angola 1995 12104952