我有一个问题,我似乎没弄明白。 我想从我的
发送一个http请求Angular客户:
import Data.List.NonEmpty as NE (NonEmpty(..), (<|), head, tail)
splitStringOnDelimeter :: String -> Char -> NonEmpty String
splitStringOnDelimeter string delimiter = foldr f (pure "") string
where f h split = if h == delimiter
then ("" <| split)
else (h : NE.head split) :| NE.tail split
到我使用CORS注释的SpringBoot后端:
const url = 'http://localhost:8080/api';
console.log(this.http.get(url).subscribe(data => this.greeting = data));
但是我收到一个错误,它被阻止并重定向我一直登录。
@CrossOrigin(origins = "http://localhost:4200/", maxAge = 3600)
@RequestMapping("/api/")
public Map<String,Object> home() {
Map<String,Object> model = new HashMap<String,Object>();
model.put("id", UUID.randomUUID().toString());
model.put("content", "Hello World");
return model;
}
有没有办法改变它?
我感谢任何有关此事的暗示或帮助。我想了解为什么会出现这个问题。
答案 0 :(得分:5)
您的RequestMapping
中有错误,因为您使用了@RequestMapping("/api/")
,这将被评估为http://your_url/api//
。您的控制器中不存在此类映射,因此它会为您提供CORS Origin错误。
只需从/
移除尾随@RequestMapping("/api/")
,即可@RequestMapping("/api")
。
您的课程应如下所示,
@RestController
@CrossOrigin(origins = "http://localhost:4200")
public class DemoController {
@RequestMapping(value = "/api", method = RequestMethod.GET)
public Map<String,Object> home() {
Map<String,Object> model = new HashMap<String,Object>();
model.put("id", UUID.randomUUID().toString());
model.put("content", "Hello World");
return model;
}
}
答案 1 :(得分:1)
这是服务器端的问题。您所要做的就是在服务器端执行一个组件,它将解决问题。或参考here
请遵循以下代码:
@Component
@Order(Ordered.HIGHEST_PRECEDENCE)
public class RequestFilter implements Filter {
public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) {
HttpServletResponse response = (HttpServletResponse) res;
HttpServletRequest request = (HttpServletRequest) req;
response.setHeader("Access-Control-Allow-Origin", "http://localhost:4200");
response.setHeader("Access-Control-Allow-Methods", "POST, PUT, GET, OPTIONS, DELETE");
response.setHeader("Access-Control-Allow-Headers", "x-requested-with");
response.setHeader("Access-Control-Max-Age", "3600");
response.setHeader("Access-Control-Allow-Credentials", "true");
if (!(request.getMethod().equalsIgnoreCase("OPTIONS"))) {
try {
chain.doFilter(req, res);
} catch(Exception e) {
e.printStackTrace();
}
} else {
System.out.println("Pre-flight");
response.setHeader("Access-Control-Allow-Methods", "POST,GET,DELETE");
response.setHeader("Access-Control-Max-Age", "3600");
response.setHeader("Access-Control-Allow-Headers", "authorization, content-type," +
"access-control-request-headers,access-control-request-method,accept,origin,authorization,x-requested-with");
response.setStatus(HttpServletResponse.SC_OK);
}
}
}
答案 2 :(得分:0)
由于您已选择为自己的应用添加注释,因此必须单独为每种方法提供@CrossOrigin
注释。这意味着您还必须:
@CrossOrigin(origins = "http://localhost:4200/", maxAge = 3600)
@RequestMapping("/login/")
public Map<String,Object> login() {
/* ... */
}
参考:https://spring.io/guides/gs/rest-service-cors/#_enabling_cors
答案 3 :(得分:0)
不是使用@Crossorigin
注释每个方法,而是可以使用filter
中的web.xml
,如下所述
将以下过滤器添加到web.xml
文件。
<filter>
<filter-name>cors</filter-name>
<filter-class>com.thetransactioncompany.cors.CORSFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>cors</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
下面给出了所述罐子的依赖性。
<dependency>
<groupId>com.thetransactioncompany</groupId>
<artifactId>cors-filter</artifactId>
<version>2.5</version>
</dependency>
多数民众赞成 - 完成。