Django多条件声明

Question

我在Django HTML模板中使用以下代码。但是，它非常重复。如何简化此代码？

它转换为，＆＃34;如果您不是员工，则可以看到nav.html。如果您是员工，只有在这4页上才能看到nav.html。＆＃34;

{% if not request.user.is_staff %}
    {% include ‘nav.html’ %}
    {% else %}
        {% if request.get_full_path == ‘/one/’ %}
            {% include ‘nav.html’ %}
        {% if request.get_full_path == ‘/two/’ %}
            {% include ‘nav.html’ %}
        {% if request.get_full_path == ‘/three/’ %}
            {% include ‘nav.html’ %}
        {% if request.get_full_path == ‘/four/’ %}
            {% include ‘nav.html’ %}
    {% endif %}
{% endif %}

Answer 1

从您的视图中，您可以发送包含要显示nav.html的路径的列表。像，

allowed_paths = ['/one/', '/two/', '/three/', '/fourth/']

在您的模板中，您可以这样做，

{% if not request.user.is_staff or request.get_full_path in allowed_paths %}
   {% include 'nav.html' %}
{% endif %}