Question

它不是override single route in symfony2的副本。请耐心等待，仔细阅读我的问题。

我的问题与上述问题不同。所以，我的Symfony应用程序有一个标准的结构。但它以特定方式配置。

app / config / routing.yml包含多个捆绑路由，例如：

_project_custom1:
    resource: "@ProjectCustom1Bundle/Resources/config/routing.yml"
    prefix:   /custom1
_project_custom2:
    resource: "@ProjectCustom2Bundle/Resources/config/routing.yml"
    prefix:   /custom2

src / 目录有两个捆绑包和下一个结构，例如

Common/AdminBundle/Resources/config/routing.yml Common/AdminBundle/Resources/config/routing_dashboard.yml

routing.yml包含下一行：

admin_dashboard_content: resource: "@CommonAdminBundle/Resources/config/routing_dashboard.yml" prefix: /dashboard

routing_dashboard.yml包含：

admin_dashboard_license_content: path: /license-content defaults: { _controller: CommonAdminBundle:Dashboard:licenseContent }

下一个捆绑包是自定义捆绑包。如何扩展DashboardController，覆盖licenseContentAction并仅覆盖一条（/license-content）路由并使Symfony使用我的自定义捆绑配置？

复制相同的结构无效。根据我的解释，我写了这样的话：

<?php
namespace Custom\Custom1\Controller;
use Common\AdminBundle\Controller\DashboardController as BaseController;
class DashboardController extends BaseController
{
    public function licenseContentAction()
    {
       //return parent::licenseContentAction();
       die("HELLO!");
    }
}

如何为make扩展方法构建路由文件？

Answer 1

您需要做的就是将这些行添加到public class Notificaciones { private WSPradera.ServicioSoapClient WPredial = new WSPradera.ServicioSoapClient(); private WSApartado.ServicioSoapClient WPredialApartado = new WSApartado.ServicioSoapClient(); private WSCopacabana.ServicioSoapClient WPredialCopacabana = new WSCopacabana.ServicioSoapClient(); private WSSanPedroMilagros.ServicioSoapClient WPredialSanPedroMilagros = new WSSanPedroMilagros.ServicioSoapClient(); public Notificaciones(PropiedadesPSE obj) { this.objPropiedades = obj; } #region Apartadó public bool Apartado() { bool flag = true; try { if (this.objPropiedades.TransactionStatus != "A") { return flag; } XElement xml = new XElement("referencia", this.objPropiedades.Numfactura); XElement notificarPago = this.WPredialApartado.GetNotificarPago(xml); XmlSerializer serializer = new XmlSerializer(typeof(cliente)); StringReader textReader = new StringReader(notificarPago.ToString()); cliente cliente = (cliente)serializer.Deserialize(textReader); if (cliente.ToString() != "") { flag = true; } } catch (Exception exception) { this.LogException(Regex.Replace(string.Concat(new object[] { exception.Message, " ", exception.InnerException, " ", exception.StackTrace }), @"\t|\n|\r", "").Replace("'", "")); throw exception; } return flag; } #endregion #region Copacabana public bool Copacabana() { bool flag = true; try { if (this.objPropiedades.TransactionStatus != "A") { return flag; } XElement xml = new XElement("referencia", this.objPropiedades.Numfactura); XElement notificarPago = this.WPredialCopacabana.GetNotificarPago(xml); XmlSerializer serializer = new XmlSerializer(typeof(cliente)); StringReader textReader = new StringReader(notificarPago.ToString()); cliente cliente = (cliente)serializer.Deserialize(textReader); if (cliente.ToString() != "") { flag = true; } } catch (Exception exception) { this.LogException(Regex.Replace(string.Concat(new object[] { exception.Message, " ", exception.InnerException, " ", exception.StackTrace }), @"\t|\n|\r", "").Replace("'", "")); throw exception; } return flag; } }文件中。

app/config/routing.yml

使用admin_dashboard_license_content: path: /dashboard/license-content defaults: { _controller: CustomBundle:Dashboard:licenseContent }方法创建一个DashboardController扩展基本Symfony控制器到licenseContentAction命名空间。

现在魔术......

如果要保留路径，则必须在CustomBundle文件的开头添加这些行。路线的名称必须不同（唯一），当然路径必须与覆盖路径相同。

Symfony查找路径，并在匹配时立即将请求重定向到相应的控制器操作。

如果要更改路径，请在routing.yml文件的末尾添加这些行。路线的名称必须相同。我不确定先前定义的路径（路径）是否仍然存在，我想是的，如果使用此路径进行的请求仍在处理中......

Symfony将路由收集到一个数组中，其中键是路径的名称。通过在文件末尾添加具有相同名称的路由，先前定义的路由将被覆盖。

如何在Symfony2中覆盖路由

1 个答案: