我有5个div的页面。我的div有不同的高度(它的适应性)。当我滚动当前div的一半时,如何通过鼠标转到下一个div?
我尝试使用fullpage.js和onepage.js,但它不适合我,因为我的div必须是不同的高度
#first {
width:100vw;
height:700px;
background-color:lightyellow;
text-align:center;
}
#second {
width:100vw;
height:700px;
background-color:lightblue;
text-align:center;
}
#third {
width:100vw;
height:1000px;
background-color:lightpink;
text-align:center;
}
#fourht {
width:100vw;
height:1500px;
background-color:lightgreen;
text-align:center;
}
#fiveth {
width:100vw;
height:800px;
background-color:lightgray;
text-align:center;
}

<div id="first">1 div</div>
<div id="second">2 div</div>
<div id="third">3 div</div>
<div id="fourht">4 div</div>
<div id="fiveth">5 div</div>
&#13;
答案 0 :(得分:0)
您需要获取高度当前有效元素,并在滚动,一页和整页上为容器转换翻译(0, - 高度)与此合作。
答案 1 :(得分:0)
var $container = $('.container');
var $elem = $container.find('.elem');
var $active = $container.find('.active').height();
$(window).on('scroll',function(){
$container.css({"transform":"translate(0, -" + $active + "px)"});
});
&#13;
body{
height: 100%;
}
.container{
transition: 1s all;
}
#first {
width:100vw;
height:700px;
background-color:lightyellow;
text-align:center;
}
#second {
width:100vw;
height:700px;
background-color:lightblue;
text-align:center;
}
#third {
width:100vw;
height:1000px;
background-color:lightpink;
text-align:center;
}
#fourht {
width:100vw;
height:1500px;
background-color:lightgreen;
text-align:center;
}
#fiveth {
width:100vw;
height:800px;
background-color:lightgray;
text-align:center;
}
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<div id="first" class="elem active">1 div</div>
<div id="second" class="elem">2 div</div>
<div id="third" class="elem">3 div</div>
<div id="fourht" class="elem">4 div</div>
<div id="fiveth" class="elem">5 div</div>
</div>
&#13;
答案 2 :(得分:0)
我创建了我的版本。看看这个https://codepen.io/damates/pen/VXdKjR。
Jquery的:
$("#nextDiv, #previousDiv").click(function(){
actualTopOffset = $(window).scrollTop();
areas = $(".area");
find = false;
newPosition = 0;
type = $(this).attr("data-type");
areasCount = $(areas).length;
$.each(areas, function(index, val) {
if(type == "next"){//if we click to go next area
if($(areas).length > (index+1)){
if(actualTopOffset < $(areas[index+1]).offset().top && !find){// ask if area has top offset higher. If yes set new position
find = true;
newPosition = $(areas[index+1]).offset().top;
}
}
}else if(type == "prev"){ //if we click to go previous area
areasCount--;
if((areasCount) >= 0){
if(actualTopOffset > $(areas[areasCount]).offset().top && !find){// ask if area has top offset lower. If yes set new position
find = true;
newPosition = $(areas[areasCount]).offset().top;
}
}
}
});
if(find){ //If we found new position scroll on new position
$('html, body').animate({
scrollTop: newPosition
}, 1000);
}
});
CSS:
#first {
width:100vw;
height:700px;
background-color:lightyellow;
text-align:center;
}
#second {
width:100vw;
height:700px;
background-color:lightblue;
text-align:center;
}
#third {
width:100vw;
height:1000px;
background-color:lightpink;
text-align:center;
}
#fourht {
width:100vw;
height:1500px;
background-color:lightgreen;
text-align:center;
}
#fiveth {
width:100vw;
height:800px;
background-color:lightgray;
text-align:center;
}
#nextDiv, #previousDiv{
position: fixed;
top: 20px;
background: red;
}
#previousDiv{
top: 0px;
}
HTML:
<div id="first" class="area">1 div</div>
<div id="second" class="area">2 div</div>
<div id="third" class="area">3 div</div>
<div id="fourht" class="area">4 div</div>
<div id="fiveth" class="area">5 div</div>
<div id="previousDiv" data-type="prev">Previous div</div>
使用滚动编辑版本
我更改了滚动脚本。看看https://codepen.io/damates/pen/VXdKjR