Question

我有一个如下所示的数据库表。

这里我在parent_sku列上使用group by。这是我的查询及其结果。

SELECT
  domain,
  parent,
  parent_name,
  parent_sku,
  SUM(qty)        AS sales,
  SUM(gross)      AS revenue,
  SUM(net)        AS net_revenue,
  SUM(refund_qty) AS returns,
  created_at
FROM report_byproducts_name
GROUP BY parent_sku
ORDER BY sales DESC
LIMIT 50

但我想优先考虑域名。就像我优先考虑itusthaves域一样，它应该将结果作为domain = themusthaves and parent = 450212给出相同的组。目前，我总是收到domain=tmhde和parent=325227

预期结果

注意：请忽略created_at列

任何建议都将受到赞赏

由于

我在这里添加SQL Fiddle

Answer 1

我认为您需要聚合更多列，然后加入到您的表中以获取相关的非聚合列

   select domain,
         parent,
         parent_name,parent_sku,
         sumsales,sumrevenue,sumnet_revenue,sumreturns
from report_byproducts_name
Join
(
SELECT
  max(parent) maxparent,
  parent_sku aggsparent_sku,
  SUM(sales)        AS sumsales,
  SUM(revenue)      AS sumrevenue,
  SUM(net_revenue)  AS sumnet_revenue,
  SUM(returns) AS sumreturns
FROM report_byproducts_name
GROUP BY parent_sku
) aggs on aggs.maxparent = parent and aggs.aggsparent_sku = parent_sku;

+--------------+--------+--------------------------------+------------+----------+-------------------+-------------------+------------+
| domain       | parent | parent_name                    | parent_sku | sumsales | sumrevenue        | sumnet_revenue    | sumreturns |
+--------------+--------+--------------------------------+------------+----------+-------------------+-------------------+------------+
| themusthaves | 450212 | Pailletten Damaged Jeans Grijs | 311        |      350 | 13692.89013671875 | 11360.31005859375 |          1 |
+--------------+--------+--------------------------------+------------+----------+-------------------+-------------------+------------+
1 row in set (0.00 sec)

我可以建议您将浮点字段更改为十进制（10,2）。

Answer 2

您可以通过创建temp表来实现此目的。您可以这样做：

WITH temp AS
(
SELECT
  parent_sku,
  SUM(qty)        AS sales,
  SUM(gross)      AS revenue,
  SUM(net)        AS net_revenue,
  SUM(refund_qty) AS returns,
  created_at
FROM report_byproducts_name
GROUP BY parent_sku
)
SELECT * FROM report_byproducts_name
WHERE parent_sku IN (SELECT parent_sku FROM temp) AND domain = 'themusthaves'

您可以在Where子句中给予优先权。

Answer 3

感谢您的支持。我可以使用如下的子查询获得预期的结果。我不知道方式是否正确，但我在这里发布我的答案，通过该答案，我可以得到预期的结果。通过我将等待更好的建议，以获得预期的结果。

SELECT 
  (SELECT domain FROM report_byproducts_name WHERE domain='themusthaves' AND parent_sku=rbn.parent_sku) as domain,
  (SELECT parent FROM report_byproducts_name WHERE domain='themusthaves' AND parent_sku=rbn.parent_sku) as parent,
  parent_name,
  parent_sku, 
  SUM(sales) as sales, 
  SUM(revenue) as revenue, 
  SUM(net_revenue) as net_revenue, 
  SUM(returns) as returns,
  created_at 
FROM report_byproducts_name rbn 
GROUP by parent_sku 
ORDER BY sales DESC 
LIMIT 50

预期结果为SQL Fiddle

在mysql的其他行中，列值优先于列值

3 个答案: