Question

我需要查询信息表单数据库CONSTRUCT { ?film wdt:P31 wd:Q11424 . ?film rdfs:label ?filmLabel . } WHERE { ?film wdt:P31 wd:Q11424 . hint:Query hint:queryEngineChunkHandler "Managed" . # hint:Query hint:constructDistinctSPO false . SERVICE wikibase:label { bd:serviceParam wikibase:language "en" . } } 我的代码可以显示1页

我的控制器

[company name ,company address]

主刀片

public function index()
{
    $footer = DB::table('pjt_setting')->pluck('value','setting_name')->toArray();
    //dd($footer);
    return view('frontend.index',compact('footer'));
}

页脚刀片

<!-- topbar -->
@include('frontend.layouts.topbar')
<!-- top -->
@include('frontend.layouts.nav')
<!-- header slide -->
<!-- Main content -->
    @yield('content')
<!-- /.content -->
<footer class="footer-distributed">
    @include('frontend.layouts.footer')
</footer>

索引页面没问题但是，我链接到联系页面显示错误<div class="row"> <div class="col-md-6"> <div class="footer-left"> <h3>{{ $footer["companyname"]}}</h3> <p class="footer-company-name">Phuket Jet Tour © 2018</p> </div> </div> <div class="footer-center"></div> <div class="col-md-6"> <div class="footer-right"> <div class="companyaddress"> <i class="fa fa-map-marker"></i> <p>{{ $footer["companyaddress"] }}</p> </div> <div> <i class="fa fa-phone"></i> <p>{{ $footer["phone"] }}</p> </div> <div> <i class="fa fa-envelope"></i> <p><a href="mailto:{{ $footer["email"] }}">{{ $footer["email"] }}</a></p> </div> </div> </div>。我如何编辑

Answer 1

在$footer视图中传递contact：

$footer = DB::table('pjt_setting')->pluck('value','setting_name')->toArray();
return view('frontend.contact-us',compact('footer'));

对于每share

，footer来自base controller view的最佳方法是

class BaseController extends \Controller
{

   protected $footer;

   public function __construct() 
   {
       $this->footer = DB::table('pjt_setting')->pluck('value','setting_name')->toArray();
       View::share('footer', $footer);
   }

}

    #use this only on grayscaled image
    thresh = cv2.threshold(yourImage, 40, 255, cv2.THRESH_BINARY)[1]

    # dilate the thresholded image to fill in holes, then find contours
    # on thresholded image
    thresh = cv2.dilate(thresh, None, iterations=2)
    (_,cnts, _) = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL,
        cv2.CHAIN_APPROX_SIMPLE)

    largest = max(cnts)

Answer 2

你可以这样做@ Sohel0415

或者你可以使用Trait。

来自db中的页脚查询数据显示在master.blade laravel 5.4中

2 个答案: