Question

我必须对我必须生成4个随机数的Cows and Bulls game进行编码，并要求用户猜测它。过去几个小时我一直在尝试对其进行编码，但似乎无法提出解决方案。

我想要的输出是：

Welcome to cows and Bulls game.
Enter a number:     
>> 1234
2 Cows, 0 Bulls.
>> 1286 
1 Cows, 1 Bulls. 
>> 1038    
Congrats, you got it in 3 tries.

到目前为止，我已经得到了这个：

print("Welcome to Cows and Bulls game.")

import random 


def number(x, y):
  cowsNbulls = [0, 0]
  for i in range(len(x)):
    if x[1] == y[i]:
      cowsNbulls[1] += 1
    else:
      cowsNbulls[0] += 1
  return cowsNbulls;


x = str(random.randint(0, 9999))
guess = 0 

while True:
    y = input("Enter a number: ")
    count = number(x, y)
    guess += 1

    print(str(count[0]), "Cows.", str(count[1]), "Bulls")
    if count[1] == 4:
      False 
      print("Congrats, you done it in", str(guess))
    else:
      break;

输出是：

Welcome to Cows and Bull game.

Enter a number: 1234 
4 Cows, 0 Bulls.

它不会继续。我只是想知道问题是什么。

Answer 1

试试这个：

print(str(count[0]), "Cows.", str(count[1]), "Bulls")
  if count[0] == 4:
    print("Congrats, you done it in", str(guess))
    break

如果计数等于4，您想要中断while循环，否则它应该继续运行。

Answer 2

您的代码存在一些问题：

而True 语句与函数
在while语句中使用 break ，这就是为什么语句只在第一次无法获得正确的anwser时才执行一次
＆＃34; x＆amp; ý＆＃34;变量？请在将来使用有意义的变种，不仅对你而且对其他人有意义
在功能＆＃34; 数字＆＃34;你有这个验证x[1] == y[i]这不会做任何事情，它只会比较字符串的第一个字符

下面我对您的代码进行了一些修复，看看它是否是您正在寻找的类似内容：

import random

def number(rand_num, guess):
  cowsNbulls = {
    'cow': 0,
    'bull': 0,
  }

  for i in range(len(rand_num)):
    try:
      if rand_num[i] == guess[i]:
        cowsNbulls['cow'] += 1
      else:
        cowsNbulls['bull'] += 1
    except:
      pass

  return cowsNbulls;

def game_start():
  rand_number = str(random.randint(1, 9999))
  tries = 0 
  locked = True

  print("Welcome to Cows and Bulls game.")

  while locked:
    print(rand_number)
    guess = input("Enter a number (Limit = 9999): ")
    cows_n_bulls = number(rand_number, guess)
    tries += 1

    print(str(cows_n_bulls['cow']), "Cows.", str(cows_n_bulls['bull']), "Bulls")
    if cows_n_bulls['cow'] == 4:
      print("Congrats, you done it in", str(tries))
      locked = False


game_start()

实施牛和公牛游戏

2 个答案: