Question

我尝试从数据库中检索消息组，并且查询没有按created_at标志对结果进行排序。

查询如下所示：

$groups = self::
    where(function($query) use ($user_id) {
        $query->where('to_id', $user_id);
        $query->orWhere('from_id', $user_id);
    })
    ->join('users as u1', 'user_messages.to_id', 'u1.id')
    ->join('users as u2', 'user_messages.from_id', 'u2.id')
    ->select(
        'u1.nickname as u1_nickname',
        'u1.id as u1_id',
        'u2.id as u2_id',
        'u2.nickname as u2_nickname',
        'user_messages.created_at'
    )
    ->orderBy('created_at', 'desc')
    ->groupBy(
        DB::raw(
            'if (user_messages.from_id = '.$user_id.', user_messages.to_id, user_messages.from_id)'
        )
    )
    ->get()
    ->toArray();

$user_id是经过身份验证的用户。 orderBy子句未按预期工作。用户未按发送邮件的最后一个人分组。

有什么建议吗？谢谢。

Answer 1

您可以使用SELECT clients.client_id, clients.first_name, COALESCE(SUM(total_charged), 0) AS total_charged FROM clients LEFT JOIN (SELECT c.client_id, a.route_property_reg_id, COALESCE(SUM(ROUND((a.rate_charged * (1 + (tax_types.rate / 100))), 2)), 0) AS total_charged FROM route_property_reg a LEFT JOIN properties ON a.property_id = properties.property_id LEFT JOIN clients c ON properties.client_id = c.client_id LEFT JOIN tax_types ON a.tax_rate_charged = tax_types.tax_type_id WHERE NOT EXISTS( SELECT NULL FROM invoice_lines b LEFT JOIN invoices ON b.invoice_id = invoices.invoice_id LEFT JOIN clients d ON invoices.client_id = d.client_id WHERE b.route_property_reg_id = a.route_property_reg_id AND d.client_id = c.client_id) GROUP BY client_id) AS charged ON clients.client_id = charged.client_id GROUP BY clients.client_id为每封邮件获取最新的Max。查询可能像：

created_at

Laravel orderBy和groupBy with if statement

1 个答案: