Question

urls.py

from django.conf.urls import include, url
from . import views
from django.contrib.staticfiles.urls import staticfiles_urlpatterns
from django.conf.urls.static import static
from django.views.generic import TemplateView
from django.conf import settings
from .views import Search

app_name = 'base'

urlpatterns = [
    url(r'^index/$', Search.as_view(), name='index'),
    url(r'^newresume/$', views.newresume, name='newresume'),
    url(r'^profile/(?P<pk>[0-9]+)/$', views.profile, name='profile'),
    url(r'^update_info/(?P<pk>[0-9]+)/$', views.update_info, name='update_info'),
]

views.py

def profile(request, pk):
    student = get_object_or_404(Students, pk=pk)
    return render(request, 'base/profile.html', {'student': student})

_tweet_search.html

<div class="studentfio">
    <a href="{% url 'profile' pk=student.pk %}"><h4>{{ student.job }}</h4></a>
</div>

Console error

大家好，请帮我解决这个错误。我做了一个AJAX请求，在此之后我收到错误，我该如何解决？

Answer 1

<div class="studentfio">
    <a href="{% url 'base:profile' student.pk %}"><h4>{{ student.job }}</h4></a>
</div>

正如您在app_name文件中提到的urls.py，您需要在url

中提及

NoReverseMatch反向＆＃39; my_url＆＃39;未找到

1 个答案: