Question

我有两张桌子; productstorymap和stories。 productstorymap有productId和storyId列。 stories有id和status列。

我需要查询属于某个产品且具有特定状态的所有故事。我得到的最近的事情是

SELECT map.*, story.*
FROM productstorymap map, stories story
WHERE map.productId=1 AND story.status=1

但它返回了不属于产品1的故事。它返回的内容如下：

Array
(
    [0] => Array
        (
            [id] => 1
            [productId] => 1
            [storyId] => 1
            [name] => Create a User Story
            [content] => Admin should be able to create user stories.
            [duration] => 1
            [priority] => 0
            [created] => 2010-09-22 17:36:21
            [edited] => 
            [status] => 1
        )

    [1] => Array
        (
            [id] => 4
            [productId] => 1
            [storyId] => 1
            [name] => Bar
            [content] => Xyzzy!
            [duration] => 
            [priority] => 1
            [created] => 2011-02-10 17:50:56
            [edited] => 2011-02-10 17:50:56
            [status] => 1
        )

)

即使productstorymap只有两行：

ID  prodcutId   storyID
1   1           1
2   7           4

我正在使用MySQL和PHP，如果这是相关的。

Answer 1

我认为您忘记加入公共领域，我假设是productstorymap.storyID和stories.id

SELECT map.*, story.*
FROM productstorymap map, stories story
WHERE map.productId=1
     AND story.status=1
     and map.storyID = story.id

Join - 语法也可以如下所示：

SELECT map.*, story.*
FROM productstorymap map
JOIN stories story on map.storyID = story.id
WHERE map.productId=1
     AND story.status=1;

Answer 2

SELECT * 
FROM productstorymap prod
JOIN stories story ON prod.storyId = story.Id
WHERE prod.productId = 1
AND story.status = 1

Answer 3

SELECT map.*, story.*
FROM productstorymap map, stories story
WHERE map.productId=1 AND story.status=1 AND map.storyId = story.Id

这是在表之间调用JOIN。寻找它

在MySQL中一次查询两个表

3 个答案: