Question

我有一个使用for循环在SKScene周围移动矩形的函数。有没有办法让它在调用SKAction时一直移动矩形？它等待运行SKAction直到循环结束，这不是我想要做的。

以下是我的代码示例：

for i in 0...newHeights.count-1 {
     for j in stride(from: 0, to: newHeights.count-i-1, by: 1){
          let moveRect = SKAction.moveTo(x: rectangles[j].position.x, duration: 5)
          moveRect.timingMode = SKActionTimingMode.easeInEaseOut
          rectangles[j+1].run(moveRect)
          let sequence = SKAction.sequence([moveRect])
          rectangles[j+1].run(sequence)
      }
}

编辑：现在该部分正在运行，但它以意想不到的方式移动。我可以通过

来切换位置

rectangles[j].position.x = rectangles[j+1].position.x
rectangles[j+1].position.x = y

但是当我尝试使用SKActions移动它们时，它会以完全不同的方式移动它们。

let moveRect = SKAction.moveTo(x: rectangles[j+1].position.x, duration: 1)
            //moveRect.timingMode = SKActionTimingMode.easeInEaseOut
            let waitAction = SKAction.wait(forDuration: 2)
            let sequence = SKAction.sequence([moveRect, waitAction])

            let moveRect2 = SKAction.moveTo(x: y, duration: 1)
            moveRect2.timingMode = SKActionTimingMode.easeInEaseOut
            let waitAction2 = SKAction.wait(forDuration: 2)
            let sequence2 = SKAction.sequence([moveRect2, waitAction2])

            rectangles[j].run(sequence) {
                self.rectangles[j+1].run(sequence2)
            }

Answer 1

如评论中所述，将速度设置为0，然后在当前节点完成时打开下一个节点的速度

唯一的问题，0会发生什么？这是故意空白吗？

for i in 0..<newHeights.count {
     for j in stride(from: 0, to: newHeights.count-i-1, by: 1){
          let moveRect = SKAction.moveTo(x: rectangles[j].position.x, duration: 5)
          let startNextRect = SKAction.run{if (j+2 < newHeights.count){self.rectangles[j+2].speed = 1}}
          moveRect.timingMode = SKActionTimingMode.easeInEaseOut
          let seq = SKAction.sequence([moveRect,startNextRect])
          rectangles[j+1].run(seq)
          rectangles[j+1].speed = 0

      }
}
rectangles[1].speed = 1

如何在循环之前完成SKAction

1 个答案: