Question

我想知道我可以使用多线程添加10个数字，但要考虑的要点如下：

我想将（1,2）（3,4）（5,6）等数字分组，并在单独的线程中执行添加。
使用执行器future.get方法获取结果并再次对结果进行分组，例如（1,2）给出3和（3,4）给出7所以现在我想把这两个结果分组并传递给另一个线程进行加法（3,7）
重复相同的过程，直到得到结果的单个数字。

我已经过了一半，但不知道如何继续前进，我也不确定是否可以分组和添加结果的剩余部分。

public class CallableAdder implements Callable<Integer> {

Integer operand1;
Integer operand2;
CallableAdder(Integer operand1,Integer operand2)
{
    this.operand1=operand1;
    this.operand2=operand2;

}

public Integer call() throws Exception {
    System.out.println(Thread.currentThread().getName()+" says : partial Sum for " + operand1 + " and "+ operand2+ " is "  +(operand1+operand2));
    return operand1+operand2;
}

}

另一堂课：

public class ParallelAdder {
public Integer parallelSum()
{
    ExecutorService executor = Executors.newFixedThreadPool(10);
    List <Future<Integer>> list = new ArrayList<Future<Integer>>();
    int prev=0;
    for(int i=1;i<=10;i++)
    {
        if(i%2==0)         //grouping
        {
            System.out.println("Prev :" + prev + " current: " + i);
            Future<Integer> future = executor.submit(new CallableAdder(prev,i));
            list.add(future);
            continue;
        }
        prev=i;
    }
    int totsum=0;
    for(Future<Integer> fut : list)
    {
        try {
            totsum = totsum+ fut.get();  
   //This contains result from first iteration here I have added everything 
   //but what I wanted to do is create another thread and perform the same 
   //operation as I did before group and then add meaning repeating step 1 and 2
        } catch (InterruptedException e) {
            e.printStackTrace();
        } catch (ExecutionException e) {
            e.printStackTrace();
        }
    }
    executor.shutdown();
    System.out.println("Total Sum is " + totsum);
    return totsum;   
}

public int sequentialSum()
{

    Integer totsum=0;
    for(int i=0;i<=1000;i++)
    {
        totsum=totsum+i;
    }
    System.out.println("sequentialSum Total Sum is " + totsum);
    return totsum;
}

public static void main(String[] args) {

    ParallelAdder adder = new ParallelAdder();
    int pSum= adder.parallelSum();
    int sSum= adder.sequentialSum();

    System.out.println("parallel Sum equals to Sequential Sum ? " );
    System.out.println("Answer is :: "  + (pSum==sSum));

}
}

请查看并帮我解决更多代码。

如何使用执行器框架在Java中使用线程添加数字？

0 个答案: