Question

我有一个包含两列的数据库表：id和status。

status可以有三个不同的值，A，B和C。

我现在希望获得具有所有三种不同状态（id，A和B）的C个。

id status
 1 A
 2 A
 1 B
 3 A
 3 B
 3 C

Answer 1

您可以使用HAVING：

SELECT id
FROM tab
GROUP BY id
HAVING COUNT(DISTINCT status) = (SELECT COUNT(DISTINCT STATUS) FROM tab);

获得完整的行：

SELECT *
FROM tab
WHERE id IN ( SELECT id
              FROM tab
              GROUP BY id
              HAVING COUNT(DISTINCT status) = 
                   (SELECT COUNT(DISTINCT STATUS)  FROM tab) 
            );

<强> DBFiddle Demo

Answer 2

我在答案中做了两个假设。你知道吗＆＃39; A＆＃39; B＆＃39; B＆＃39;和＆＃39; C＆＃39;这些状态只会出现一次。也许在（id，status）上有一个UNIQUE约束。

SELECT id FROM tab GROUP BY id HAVING (COUNT(1) == 3);

Answer 3

如果状态列已修复，

然后你可以试试下面的东西

select id, count(distinct `status`) as ct from tab group by id having ct=3

检查Here

Answer 4

也许这很有帮助：

SELECT
  id,
  `status`,
  COUNT(tab.status) AS s
FROM
  tab
GROUP BY id
HAVING s = 3

我怎样才能获得具有所有状态的id？

4 个答案: