Question

我不会撒谎，这是一个新的任务，我无法解决这个问题。

到目前为止，从这个查询中，我可以获得每个公寓大楼的所有租金收入。我只需要能够按月分开它。

这是我目前的查询：

SELECT cmplxName AS 'Complex Name', rentTrandate AS 'month' , sum(rentPaid) AS 'Rent Revenue'
FROM complex
INNER JOIN apartment
ON complex.cmplxID = apartment.cmplxID 
INNER JOIN lease
ON apartment.aptNumber = lease.aptNumber and apartment.cmplxID = lease.cmplxID
INNER JOIN rent
ON lease.leaseID = rent.leaseID
GROUP BY cmplxName

这是数据的外观：

complexName     month   rentRevenue
Fox Run         March   1250.00
Oak Meadows     March   1500.00
Oak Meadows     April   700.00
Villa Maria     March   1200.00
Villa Maria     April   600.00

这就是我的数据现在的样子：

Fox Run     2015-03-01  1250.00
Oak Meadows 2015-03-01  2200.00
Villa Maria 2015-03-01  1800.00

感谢您的耐心等待。

Answer 1

嗨keelsinith这将完成如下使用此SELECT DATENAME（月，rentTrandate） DATENAME是一个SQL方法，需要2个参数DATETIME（interval，YourDateValue）间隔需要一年，一周，一个月

SELECT cmplxName AS 'Complex Name', SELECT DATENAME(month,rentTrandate) AS 'month' , sum(rentPaid) AS 'Rent Revenue'

FROM complex INNER JOIN公寓 ON complex.cmplxID = apartment.cmplxID INNER JOIN租约 ON apartment.aptNumber = lease.aptNumber和apartment.cmplxID = lease.cmplxID INNER JOIN租金 ON lease.leaseID = rent.leaseID GROUP BY cmplxName

Answer 2

您只需更改月份字段的定义，并将分组更改为按组分组以及复杂名称：

SELECT cmplxName AS 'Complex Name', MONTHNAME(rentTrandate) AS 'month' , sum(rentPaid) AS 'Rent Revenue'
FROM complex
INNER JOIN apartment
ON complex.cmplxID = apartment.cmplxID 
INNER JOIN lease
ON apartment.aptNumber = lease.aptNumber and apartment.cmplxID = lease.cmplxID
INNER JOIN rent
ON lease.leaseID = rent.leaseID
GROUP BY cmplxName, month

Answer 3

我建议您同时包含年份和月份。此外，强烈建议使用表别名和限定列名称：

SELECT c.mplxName as Complex_Name, year(r.rentTrandate) as yyyy,
       month(r.rentTrandate) as mm, sum(rentPaid) as Rent_Revenue
FROM complex c INNER JOIN
     apartment a
     ON c.cmplxID = a.cmplxID INNER JOIN
     lease l
     ON a.aptNumber = l.aptNumber and a.cmplxID = l.cmplxID INNER JOIN
     rent r
     ON l.leaseID = r.leaseID
GROUP BY c.cmplxName, year(r.rentTrandate), month(r.rentTrandate)
ORDER BY c.cmplxName, year(r.rentTrandate), month(r.rentTrandate);

这将月份作为数字，但这更适合于对结果集进行排序。

在sql中逐月分配租金支付

3 个答案: