Question

首先，好消息：我只有一张桌子。

现在，我有3个类似的查询：

SELECT id FROM (
  SELECT * FROM my_table
  ORDER BY columnA
  DESC LIMIT 600
  ) AS aliasA
WHERE (revenue > 10000);

SELECT id FROM (
  SELECT * FROM my_table
  ORDER BY columnB
  DESC LIMIT 400, 999999999999
  ) AS aliasB
WHERE (revenue > 10000);

SELECT id FROM (
  SELECT * FROM my_table
  ORDER BY columnC
  DESC LIMIT 800;
  ) AS aliasC
WHERE (revenue > 10000);

注意WHERE子句是相同的。

有没有办法组合这3个查询，以便我可以从3个子查询的交集中搜索（查找匹配所有3个子查询的行，以及我的WHERE子句）？

顺便说一句，如果我的单个查询（合并之前）可以简化，请告诉我。

谢谢！

Answer 1

SELECT ID FROM

(SELECT id FROM (
    SELECT * 
    FROM my_table
    WHERE (revenue > 10000)
    ORDER BY columnA DESC 
   LIMIT 600
) AS aliasA) AS a

INNER JOIN (
  SELECT id FROM (
     SELECT * 
     FROM my_table
     WHERE (revenue > 10000)
     ORDER BY columnB DESC
     LIMIT 400, 999999999999
  ) AS aliasB
) 
AS b ON a.id = b.id

INNER JOIN (
  SELECT id FROM (
    SELECT * 
    FROM my_table
    WHERE (revenue > 10000)
    ORDER BY columnC DESC
    LIMIT 800
  ) AS aliasC
) 
AS c ON a.id = c.id AND b.id = c.id

然后你可以搜索这个查询

Answer 2

您可以在key：id上使用INNER JOIN，然后将where子句放在最后。所有3个查询都在使用收入＆gt; 10000，它可以组合在onenwhere子句中，因为所有收入列都来自同一个表。

select t1.id from (
SELECT id, revenue FROM (
  SELECT * FROM my_table
  ORDER BY columnA
  DESC LIMIT 600
  ) AS aliasA) as t1
INNER JOIN (
SELECT id FROM (
  SELECT * FROM my_table
  ORDER BY columnB
  DESC LIMIT 400, 999999999999
  ) AS aliasB) as t2 on t1.id= t2.id
INNER JOIN (
SELECT id, revenue FROM (
 SELECT * FROM my_table
 ORDER BY columnC
  DESC LIMIT 800;
) AS aliasC) as t3 on t1.id =t3.id
WHERE (t1.revenue > 10000);

Answer 3

在您的情况下，最佳解决方案是JOIN USING（id）：

sudo chown root:root ~/.aws

如果您的子查询中没有LIMIT，则可以使用id IN：

SELECT id 
FROM (SELECT id FROM my_table ORDER BY columnA DESC LIMIT 600)
aliasA
JOIN (SELECT id FROM my_table ORDER BY columnB DESC LIMIT 400, 999999999999)
aliasB USING (id)
JOIN (SELECT id FROM my_table ORDER BY columnC DESC LIMIT 800)
aliasC USING (id)
JOIN my_table USING (id)
WHERE (revenue > 10000);

但子查询中不支持LIMIT，因此您无法执行此操作。

如果您使用的是其他SQL，则可以使用INTERSECT：

SELECT id FROM my_table
WHERE (
id IN (SELECT id FROM my_table ORDER BY columnA DESC LIMIT 600)
AND
id IN (SELECT id FROM my_table ORDER BY columnB DESC LIMIT 400, 999999999999)
AND
id IN (SELECT id FROM my_table ORDER BY columnC DESC LIMIT 800)
AND
revenue > 10000
)

然而，MySql不支持INTERSECT。

如何从多个子查询结果中选择？

3 个答案: