Question

在这种情况下，我不能使用for循环或do while循环。我在一个介绍编程课，似乎无法为我工作，我需要一些帮助。我们要做的是获取一个文本文件make java read it并找出有多少左括号，右括号，逗号，句号，感叹号，问号，星号以及文本文件中有多少个元音。我面临的问题是，我似乎无法更新计数器更正，我也无法将input.hasNext（）作为变量。任何事都有帮助，提前谢谢。

代码在这里：

import java.util.Scanner; 
import java.io.*;

public class PP5_15
{
public static void main(String[]args) throws IOException
{
Scanner input = new Scanner(new File("Chp5.txt")); 
input.useDelimiter("");

int R_ParCount = 0;
int L_ParCount = 0;
int ComCount = 0;
int PerCount = 0;
int ExCount = 0;
int QuCount = 0;
int AstCount = 0;
int VowCount = 0;
int NumCount = 0; 

while(input.hasNext() == true)
{
  if(input.next().contains("("))
  R_ParCount++;
  else if (input.next().contains(")"))
  L_ParCount++;
}
while(input.hasNext())
{
  if(input.next().contains("'"))
  ComCount++; 
  else if(input.next().contains("%"))
  PerCount++;
          }

System.out.println("Amount of Right Parenthese: "+R_ParCount); 
System.out.println("Amount of Left Parenthese: "+L_ParCount);
System.out.println("Amount of Commas: "+ComCount); 
System.out.println("Amount of Percent Signs: "+PerCount); 
System.out.println("Amount of Exclamation Points: "+ExCount); 
System.out.println("Amount of Question Marks: "+QuCount);
System.out.println("Amount of Astric Count: "+AstCount); 
System.out.println("Amount of Vowels: "+VowCount); 
System.out.println("Amount of Numeric Places are: "+NumCount);

}
}

Answer 1

您只需存储if($result->num_rows >0){ $json=[]; while(($row = $result->fetch_assoc())) { $json[] = $row; } echo json_encode($json); } else { echo "0 results"; }返回的值，然后进行比较：

next()

Answer 2

import java.util.Scanner;
import java.io.*;

public class CountChars
{
    public static void main(String[]args) throws IOException
    {
        // fine so far
        Scanner input = new Scanner (new File("meanVarianceRange.sh"));
        input.useDelimiter("");

        // counting everything is more easy, than counting 10 different things    
        int[] charcount = new int [256];
        // except for the vowels, which is aeiou=5 + 5 (uppercase)
        int vowels = 0;
        // not to mention 10 ciphers, if I understood correctly
        int numerics = 0;

        while (input.hasNext ())
        {
            char c = input.next ().charAt (0);
            // we use the char as index into our array and just increment
            ++charcount [c];
            // but for the vowels, we count them as group, too
            if ("aeiouAEIOU".contains ("" + c))
                ++vowels;
            // in contrast, digits are ordered in the ascii table, 
            // so we can express them as >= '0' and <= '9'
            if (c >= '0' && c <= '9')
                ++numerics;
        }
        // see, how the char itself makes the code self commenting: 
        System.out.println ("Amount of Right Parenthese: "   + charcount[')']);
        System.out.println ("Amount of Left Parenthese: "    + charcount['(']);
        System.out.println ("Amount of Commas: "             + charcount[',']);
        System.out.println ("Amount of Percent Signs: "      + charcount['%']);
        System.out.println ("Amount of Exclamation Points: " + charcount['!']);
        System.out.println ("Amount of Question Marks: "     + charcount['?']);
        System.out.println ("Amount of Astric Count: "       + charcount['*']);
        System.out.println ("Amount of Vowels: "             + vowels);
        // (charcount['a'] + charcount['a'] + charcount['e'] + charcount['i'] + charcount['o'] + charcount['u']));
        System.out.println ("Amount of Numeric Places are: " + numerics);
    }
}

由于String中的'contains'方法需要一个String，我们必须使用从char到String（长度为1）的这种特殊转换来查找我们的char：.contains ("" + c)。好吧 - 有一些替代品，比如indexOf和测试＆gt; = 0。

字符可以完美地转换为整数（但不是相反的方式）。这就是为什么我们可以使用char本身作为我们的int数组的索引，它包含charcount ['x']的值，我们在该索引处执行增量数。

请注意，我更改了输入文件名，以匹配驱动器上的内容。

测试：

Amount of Right Parenthese: 11
Amount of Left Parenthese: 11
Amount of Commas: 0
Amount of Percent Signs: 1
Amount of Exclamation Points: 1
Amount of Question Marks: 1
Amount of Astric Count: 7
Amount of Vowels: 43
Amount of Numeric Places are: 19

试图读取文本文件中的特殊字符数量

2 个答案: