Question

我创建了一个简约的Rack应用程序，它将响应

URL GET /time

使用format查询字符串参数并以指定格式返回时间。

例如，GET请求

/time?format=year%2Cmonth%2Cday

将返回带有text / plain类型和body 1970-01-01的响应。

可用时间格式：年，月，日，小时，分钟，秒
格式传递给＆＃39;格式＆＃39;按任意顺序查询字符串参数
如果时间格式中存在未知格式，则应返回状态码为400且正文为＆＃34;未知时间格式[epoch]＆＃34;
如果有多种未知格式，则应在响应正文中列出所有格式，例如：＆＃34;未知时间格式[纪元，年龄]＆＃34;
如果请求任何其他网址，则应返回状态代码为404

有我的代码：

config.ru

require_relative 'middleware/logger'
require_relative 'app'

use AppLogger
run App.new

logger.rb

require 'logger'

class AppLogger

  def initialize(app, **options)
    @logger = Logger.new(STDOUT)
    @app = app
  end

  def call(env)   
    @logger.info(env)
    @app.call(env)
  end

end

app.rb

class App

  def call(env)  
    @query = env["QUERY_STRING"] 
    @path = env["REQUEST_PATH"]
    @user_format = (Rack::Utils.parse_nested_query(@query)).values.join.split(",")
    @acceptable_format = %w(year month day hour minute second)
    [status, headers, body]
  end

  private 

  def status
    if @path == "/time" && acceptably?
      200
    elsif @path == "/time"
      400
    else
      404
    end      

  end

  def headers
    { 'Content-Type' => 'text/plain' }
  end

  def body
    if @path == "/time" && acceptably?
      **#to do** 
    elsif @path == "/time"
      ["Unknown time format #{unknown_time_format}"]
    else
      ['Not found']    
    end
  end

  def acceptably?
    (@user_format - @acceptable_format).empty?
  end 

  def unknown_time_format
    @user_format - @acceptable_format
  end

end

Answer 1

def convert_user_format
  @user_format.map! { |t| case t
                            when "year"
                              t = Time.now.year
                            when "month"
                              t = Time.now.month
                            when "day"
                              t = Time.now.day
                            when "hour"
                              t = Time.now.hour
                            when "minute"
                              t = Time.now.min
                            when "second"
                              t = Time.now.sec        
                          end     
                        }
  @user_format.join("-")                           
end

def body
  if @path == "/time" && acceptably?
    [convert_user_format]
...

简单的Rack应用程序将响应URL GET / time？format = year％2Cmonth％2Cday with 1970-01-01

1 个答案: