是||的第二个表达式如果第一个表达式在c ++中为真，则跳过？

Question

int found = 0, count = 5;
if (!found || --count == 0)
    cout << "danger" << endl;
    cout << "count = " << count << endl;

预期输出为danger，count = 4 为什么计数不减一？