Question

所以我想在我的计算机上将我数据库的数据添加到mlab数据库中。我复制了数据（我假设是JSON）并尝试将其粘贴到我的mlab数据库中的集合中。

现在，问题是我的数据库中的ObjectIds导致错误，因为它不是有效的JSON。有谁知道如何解决这个问题？

示例文档

path

Mlab错误

JSON验证错误关闭我们在解析您的时遇到错误 JSON。请检查您的语法（例如，确保您使用的是双倍引用您的字段名称和值），然后重试。

我测试了JSON lint中的代码，它给了我这个错误：

{
    "_id" : ObjectId("5a8ae78844a5ba0d448a4cf7"),
    "ratings" : [],
    "reviews" : [],
    "title" : "The Shape of Water",
    "director" : "Guillermo Del Toro",
    "length" : 123,
    "genre" : "Drama",
    "description" : "At a top secret research facility in the 1960s, a lonely janitor forms a unique relationship with an amphibious creature that is being held in captivity.",
    "actors" : "French chick, Fish Dude",
    "year" : 2018,
    "pictureUrl" : "https://media.pathe.nl/nocropthumb/620x955/gfx_content/other/api/filmdepot/v1/movie/download/23452_94164_ps_sd-high.jpg",
    "__v" : 18,
    "averageRating" : 4
}

Answer 1

mLab上的数据编辑器使用严格的MongoDB Extended JSON。有关详细信息，请参阅此处：docs.mongodb.com/manual/reference/mongodb-extended-json

在严格的MongoDB中，扩展JSON ObjectId("<id>")需要{ "$oid": "<id>" }。试试这个：

{
    "_id" : { 
        "$oid": "5a8ae78844a5ba0d448a4cf7" 
    },
    "ratings" : [],
    "reviews" : [],
    "title" : "The Shape of Water",
    "director" : "Guillermo Del Toro",
    "length" : 123,
    "genre" : "Drama",
    "description" : "At a top secret research facility in the 1960s, a lonely janitor forms a unique relationship with an amphibious creature that is being held in captivity.",
    "actors" : "French chick, Fish Dude",
    "year" : 2018,
    "pictureUrl" : "https://media.pathe.nl/nocropthumb/620x955/gfx_content/other/api/filmdepot/v1/movie/download/23452_94164_ps_sd-high.jpg",
    "__v" : 18,
    "averageRating" : 4
}

JSON：无法将我的mongodb数据库的ObjectIds放入mLab集合中

1 个答案: