例如我有这段代码:
public class Weather {
private int temperature;
//Set temperature to t.
//If t goes below -15, temperature should become -15.
//If t goes above 40, temperature should become 40.
//If t is already between -15 and 40, it should not be changed.
public void setTemperature(int t){
if(t>= -15 && t<= 40){
temperature = t;
}
else if(t< -15){
temperature = -15;
}
else if(t> 40){
temperature = 40;
}
}
}
我的问题是,如果说客户写了
Weather temp1 = new Weather();
temp1.setTemperature(-20);
temp1.setTemperature(10);
然后温度实际上会设置为10而不是-15,因为setTemperature函数被调用两次。如果温度已经设置为-15到40之间的值,我需要我的代码忽略setter函数的任何未来调用。我该怎么办?上面的代码就是我现在所有的......
答案 0 :(得分:1)
尝试使用Integer而不是nullable状态:
private Integer temperature = null;
public void setTemperature(int t){
if( temperature != null ) return;
if(t>= -15 && t<= 40){
temperature = t;
}
else if(t< -15){
temperature = -15;
}
else if(t> 40){
temperature = 40;
}
}
}
答案 1 :(得分:0)
使用temperature
初始化Integer.MAX_VALUE
,如果其值小于setTemperature
,则不要在public class TestMan {
public class Weather {
private int temperature = Integer.MAX_VALUE;
//Set temperature to t.
//If t goes below -15, temperature should become -15.
//If t goes above 40, temperature should become 40.
//If t is already between -15 and 40, it should not be changed.
public void setTemperature(int t){
if (temperature < Integer.MAX_VALUE) return;
if(t>= -15 && t<= 40){
temperature = t;
}
else if(t< -15){
temperature = -15;
}
else if(t> 40){
temperature = 40;
}
}
}
内执行任何操作:
{{1}}
答案 2 :(得分:0)
根据您的要求:
如果温度已经设置为-15到40之间的值,我需要我的代码忽略setter函数的任何调用。
你可以使用一个标志来确定你之前是否已经调用了setter,如果是,那么检查以前的temperature
是否在你的范围内,或者不在下面的代码中:
public class Weather {
private int temperature;
private boolean sette_called = false;
//Set temperature to t.
//If t goes below -15, temperature should become -15.
//If t goes above 40, temperature should become 40.
//If t is already between -15 and 40, it should not be changed.
public void setTemperature(int t){
if (sette_called)
{
if (temperature >= -15 && temperature <= 40)
return;
}
if(t>= -15 && t<= 40){
temperature = t;
}
else if(t< -15){
temperature = -15;
}
else if(t> 40){
temperature = 40;
}
sette_called = true;
}
}
答案 3 :(得分:0)
尝试标记关键字,如果它是真的..我永远不会设置任何未来的温度 {
private int temperature;
bool flag = false;
//Set temperature to t.
//If t goes below -15, temperature should become -15.
//If t goes above 40, temperature should become 40.
//If t is already between -15 and 40, it should not be changed.
public int setTemperature(int t)
{
if (flag == false)
{
if (t >= -15 && t <= 40)
{
temperature = t;
flag = true;
}
else if (t < -15)
{
temperature = -15;
flag = true;
}
else if (t > 40)
{
temperature = 40;
flag = true;
}
return temperature;
}
else
{
return temperature;
}
}
答案 4 :(得分:-1)
使用Integer数据类型。设置temperature = null
。
private Integer temperature = null;
public void setTemperature(int t){
if( temperature != null) {
return;
}
if(t>= -15 && t<= 40){
temperature = t;
} else if(t< -15){
temperature = -15;
} else if(t> 40){
temperature = 40;
}
}