在Laravel 5.6中为孩子和孙子女申请条件

Question

我有3个表，我希望能够获取功能value_number为2且字段show_list为1

的记录

Products
|------|
|  id  |
|------|
|   1  |

Features
|------|--------------|-------------|
|  id  |   value_num  |   field_id  |        
|------|--------------|-------------|
|   1  |       2      |     1       |
|------|--------------|-------------|
|   2  |       3      |     2       |

Fields
|------|---------------|
|  id  |  show_list    |
|------|---------------|
|   1  |      1        |
|------|---------------|
|   2  |      0        |

我的模特看起来像：

产品     

namespace App\Models;

use Illuminate\Database\Eloquent\Model;

class Product extends Model
{
    public function categories()
    {
        return $this->belongsToMany(Category::class);
    }

    public function features()
    {
        return $this->belongsToMany(Feature::class);
    }
}

特性     

namespace App\Models;

use Illuminate\Database\Eloquent\Model;

class Feature extends Model
{
    public function products()
    {
        return $this->belongsToMany(Products::class);
    }

    public function field()
    {
        return $this->belongsTo(Field::class);
    }
}

字段     

namespace App\Models;

use Illuminate\Database\Eloquent\Model;

class Field extends Model
{
    public function categories()
    {
        return $this->belongsToMany(Category::class);
    }

    public function features()
    {
        return $this->hasMany(Feature::class);
    }
}

我的查询得到的最远的是：

    $category = $category->load(['products' => function ($query) {
        $query->with(['features' => function ($query) {
            $query->join('fields', 'features.field_id', '=', 'fields.id')
                ->with('field')
                ->where('show_list', 1)
                ->where('value_number', 2);
        }]);
    }]);

以下有效，但查询很可怕，我确信必须有更好的方法：

$category = $category->load(['products' => function ($query) {
    $query->with(['features' => function ($x) {
        $x->with('field')
            ->whereHas('field', function($y) {
                $y->where('show_list', 1);
            });
    }])
        ->whereHas('features', function ($query) {
            $query->where('value_number', 2);
        });}]);