Question

我尝试过很多不同的投影，但他们都说打印“无效”。如果有人能解释或编辑我的代码以便我能理解，我将不胜感激。

username = []
password = []

def account_creation():
    account = input("Would you like to make an Account? Yes or No: ")
    if account == "Yes" or "yes":
        username = input("Please make a Username: ")
        password = input("Please make a Password: ")
    else:
        return
account_creation()

def login():
    account = input("Do you have an Account? Yes or No: ")
    if account == "Yes":
        login_username = input("Plese enter your username: ")
        login_password = input("Plese enter your password: ")
    else:
        return
    if login_username and login_password == username and password:
        print("Welcome back")
    else:
        print("Invalid Username or Password")

login()

Answer 1

您需要先检查用户名 - 密码检查行（如_venky所述）：

...    
if login_username == username and login_password == password:
...

但是你在这里缺少一些更重要的东西。您正在尝试更改函数内的全局变量，因此您需要在函数体中使用global关键字和相关变量。

def account_creation():
    global username,password
    account = ... the rest of the code

为什么我的程序在正确时打印“无效的用户名或密码”

1 个答案: