Question

我是json和javascript的新手，我有以下输入：

    var input= {
    "careerLevelGroups": [
        {
            "201801": 58,
            "201802": 74,
            "careerLevel": "Analyst",
            "careerLevels": [
                {
                    "201801": 29,
                    "201802": 37,
                    "careerID": "10000100"
                },
                {
                    "201801": 29,
                    "201802": 37,
                    "careerID": "10000110"
                }
            ]
        },
        {
            "201801": 58,
            "201802": 74,
            "careerLevel": "Consultant",
            "careerLevels": [
                {
                    "201801": 29,
                    "201802": 37,
                    "careerID": "10000080"
                },
                {
                    "201801": 29,
                    "201802": 37,
                    "careerID": "10000090"
                }
            ]
        }
    ]
};

我需要创建这个结果：

    var result = {
  [

        {
           "careerLevel": "Analyst",
            "careerLevels": [
                {
                    "201801": 29,
                    "201802": 37,
                    "careerID": "10000100"
                },
                {
                    "201801": 29,
                    "201802": 37,
                    "careerID": "10000110"
                }
            ]
        },
        {

            "careerLevel": "Consultant",
            "careerLevels": [
                {
                    "201801": 29,
                    "201802": 37,
                    "careerID": "10000080"
                },
                {
                    "201801": 29,
                    "201802": 37,
                    "careerID": "10000090"
                }
            ]
        }
    ]
}

我想我需要做一些像我只需要careerLevel和careerLevels属性的地方（其余全部都应删除）。我尝试了json的循环结构和删除命令，但是没有得到正确的格式。

 let clJson = input.careerLevelGroups.forEach(element => {
  let keysToDelete = Object.keys(element).filter( // return keys with careerLevel and careerLevels);
 // delete keys

});

Answer 1

使用delete运算符删除键：

＆＃13;

var input = {
  "careerLevelGroups": [{
      "201801": 58,
      "201802": 74,
      "careerLevel": "Analyst",
      "careerLevels": [{
          "201801": 29,
          "201802": 37,
          "careerID": "10000100"
        },
        {
          "201801": 29,
          "201802": 37,
          "careerID": "10000110"
        }
      ]
    },
    {
      "201801": 58,
      "201802": 74,
      "careerLevel": "Consultant",
      "careerLevels": [{
          "201801": 29,
          "201802": 37,
          "careerID": "10000080"
        },
        {
          "201801": 29,
          "201802": 37,
          "careerID": "10000090"
        }
      ]
    }
  ]
};

const result = input.careerLevelGroups;
result.forEach(obj => {
  Object.keys(obj).forEach(key => {
    if (key !== 'careerLevel' && key !== 'careerLevels') delete obj[key];
  })
});
console.log(result);

＆＃13;

请注意，这会改变原始对象 - 它不会创建副本。

Answer 2

最简单的解决方案似乎是使用对象解构的解决方案：

＆＃13;

const input= {"careerLevelGroups": [{"201801": 58, "201802": 74, "careerLevel": "Analyst", "careerLevels": [{"201801": 29, "201802": 37, "careerID": "10000100"}, {"201801": 29, "201802": 37, "careerID": "10000110"}]}, {"201801": 58, "201802": 74, "careerLevel": "Consultant", "careerLevels": [{"201801": 29, "201802": 37, "careerID": "10000080"}, {"201801": 29, "201802": 37, "careerID": "10000090"}]}]}

const simplify = ({careerLevel, careerLevels}) => ({careerLevel, careerLevels})
const result = {careerLevelGroups: input.careerLevelGroups.map(simplify)}

console.log(result)

＆＃13;

请注意，输出与原始输出稍有不同，这不是合法的语法。

Answer 3

从对象“obj”中删除项目“xyz”的正确方法是

delete obj["xyz"];

仅删除嵌套对象中的特定键

3 个答案: